1) the x-coordinate of the system can be given as follow:
2x+3y = 5 (i)
3x+5y =7 (ii)
we multiply (i) by 5 and (ii) by 3, we have
10x+15y = 25 (a)
9x+15y =21 (b)
so (a) - (b) implies x = 4,
2) We do the same method for
{2x + y = 2
{3x + 4y = -22,
and we found y = -10,
3) for the last one,
{5x + 4y = 2
{-2y = 8 + 4x
this system is equivalent to
{5x + 4y = 2 (i)
{4x + 2y = - 8 (ii)
so, multiply (i) by 4 and (ii) by 5, and we have
20x + 16y = 8 (a)
20x + 10y = -40 (b)
elimination of x gives 6y = 48 then y= 8, we can find x fastly by replacing y=8 in (i), so 5x +4(8) =2, which implies x= -6
finally the solution is S= {(-6, 8)}
Answer:
60x-4
Step-by-step explanation:
39x+21x=60x
Therefore, you are left with 60x-4, which is in its simplest form.
Answer:The first option is correct
Step-by-step explanation:
Answer:
y = -2(x -2)^2 + 11
Step-by-step explanation:
It works well to factor the leading coefficient from the first two terms.
... y = -2(x^2 -4x) +3
Now we want to add the square of half the x-coefficient inside parentheses, and subtract the equivalent quantity outside parentheses.
... y = -2(x^2 -4x +4) +3 - (-2·4)
... y = -2(x -2)^2 +11 . . . . . . . . simplify
_____
The form given in the problem statement is called "vertex form," where the vertex of the parabola is (h, k). A graph shows us the vertex is (2, 11), so we can write the function immediately as ...
... y = -2(x -2)^2 +11
Mx = Nx - Pt
To isolate 'x', we have to group all terms that have 'x' together
We have Mx on the left-hand side of the equation and Nx on the right.
Moving Nx to the left-hand side of the equation, we have:
Mx - Nx = Pt
From here we factorize 'x'
x (M - N) = Pt
Then we divide both sides by (M-N)