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sveticcg [70]
3 years ago
6

Which graph represents y=x+3? Question 5 options:

Mathematics
2 answers:
lesya692 [45]3 years ago
7 0

Answer:

Graph B is the answer.

Step-by-step explanation:

The given equation y = x + 3 represents a linear function so graphs B or D having a line may be the answer.

Now we take the graph B.

Line in this graph passes through points (0, 3) and (-3, 0) and y intercept is 3.

Then slope of this line will be = \frac{y-y'}{x-x'}

                                                 = \frac{0-3}{-3-0}

                                                 = 1

Therefore, equation of the line in this graph will be y = x + 3

Now we take graph D which passes through (0, 3) and (3, 0) and y-intercept is 3.

Slope of the line = \frac{y-y'}{x-x'}

                            = \frac{0-3}{3-0}

                            = -1

Now the equation this line will be y = -x + 3

Therefore, the answer is Graph B.

Leno4ka [110]3 years ago
4 0

Answer:

Option 2

Step-by-step explanation:

y=x+3 is a positive slope so the line going up to the right is a positive slope and the line passes through y-intercept at 3

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vodomira [7]

Answer:

4w+4=-6

4w=-6-4

4w=-10

4w/4=-10/4

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The Viking football team won 4 out of every 5 of their football games. If they played 20 games, how many games did they lose?
alexgriva [62]

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3 years ago
Someone please help it’s the last question of my final.
Trava [24]

Answer: $46,619

»» 288.44 / 0.7%

»› 41,205

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»» 5,414

A=41,205

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3 years ago
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kodGreya [7K]

Answer:

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Expand the logarithm.<br> ln((-3e^5)/(x^3))
Valentin [98]

Answer:

ln(3) + 5 - 3ln(x) or 6.0986 - 3ln(x)

Step-by-step explanation:

ln(\frac{3e^{5} }{x^3} )

ln(\frac{3e^{5} }{x^3} ) = ln(3e^5)-ln(x^3), since ln(x/y) = ln(x)-ln(y)

ln(3e^5) = ln(3) + ln(e^5), since ln(xy) = ln(x) + ln(y)

ln(\frac{3e^{5} }{x^3} ) = ln(3) + ln(e^5)-ln(x^3)

ln(\frac{3e^{5} }{x^3} ) = ln(3) + 5ln(e) -3ln(x), since ln(x^y) = yln(x)

ln(\frac{3e^{5} }{x^3} ) = ln(3) + 5 -3ln(x) , since ln(e)=1

if needed further simplification,

ln(3) = 1.0986

ln(e) = 1

ln(\frac{3e^{5} }{x^3} ) = 6.0986 - 3ln(x)

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3 years ago
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