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Anna11 [10]
3 years ago
12

7r-15/s when r= 3 and s = 5.

Mathematics
2 answers:
alexandr1967 [171]3 years ago
7 0

Answer:

21-3=18

Hope This Helps!!!

svetoff [14.1K]3 years ago
4 0

Answer:

18

Step-by-step explanation:

7(3)= 21

15/5=3

21-3=18

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Cos 600 degrees solved by double angle formula (20 points)<br> show work please :)))
Lady_Fox [76]

Answer:

\rm\cos({600}^{ \circ} )  =-1/2

Step-by-step explanation:

we would like to solve the following using double-angle formula:

\displaystyle  \cos( {600}^{ \circ} )

there're <u>4</u><u> </u>double Angle formulas of cos function which are given by:

\displaystyle  \cos(2 \theta)  =  \begin{cases} i)\cos^{2} ( \theta)  -  { \sin}^{2}(  \theta)  \\ii) 2 { \cos}^{2}( \theta) - 1 \\iii) 1 -  { \sin}^{2}  \theta  \\  iv)\dfrac{1 -  { \tan}^{2}  \theta}{1 +  { \tan}^{2} \theta }  \end{cases}

since the question doesn't allude which one we need to utilize utilize so I would like to apply the second one, therefore

step-1: assign variables

to do so rewrite the given function:

\displaystyle  \cos( {2(300)}^{ \circ} )

so,

  • \theta =  {300}^{ \circ}

Step-2: substitute:

\rm\cos(2 \cdot {300}^{ \circ} )  = 2 \cos ^{2}  {300}^{ \circ}  - 1

recall unit circle thus cos300 is ½:

\rm\cos(2 \cdot {300}^{ \circ} )  = 2  \left( \dfrac{1}{2} \right)^2   - 1

simplify square:

\rm\cos(2 \cdot {300}^{ \circ} )  = 2\cdot \dfrac{1}{4}  - 1

reduce fraction:

\rm\cos(2 \cdot {300}^{ \circ} )  = \dfrac{1}{2}  - 1

simplify substraction and hence,

\rm\cos({600}^{ \circ} )  = \boxed{-\frac{1}{2}}

7 0
3 years ago
An opaque cylindrical tank with an open top has a diameter of 3.25 m and is completely filled with water. When the afternoon Sun
kicyunya [14]

Answer:

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Step-by-step explanation:

We must first know that the angle of refraction is given by the following equation:

n_water * sin (A_water) = n_air * sin (A_air)

where n is the refractive index, for water it is 1.33 and for air it is 1.

The angle (A) in the air is 22.8 °, and that of the water is unknown.

Replacing these values we have to:

1.33 * sin (A_water) = 1 * 0.387

sin (A_water) = 1 * 0.387 / 1.33

A_water = arc sin (0.2907) = 16.9 °

now for the tank depth:

h = D / tan (A_water)

D = 3.25

Replacing

h = 3.25 / tan 16.9 °

h = 10.69

Therefore the depth is 10.69 meters.

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3 years ago
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dangina [55]

Answer:

121.5

Step-by-step explanation:

40.5*3=121.5

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Sholpan [36]
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3 years ago
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