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ELEN [110]
3 years ago
15

Can someone please help me on this? Find sine A and sine B. How long is the hypotenuse of triangle ABC?

Mathematics
1 answer:
finlep [7]3 years ago
8 0

Answer:

10

Step-by-step explanation:

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What is the answer to (6x-2)-(-x+5)
UNO [17]

Answer:

(6x-2) - (-x+5)

= 6x-2 +x -5

= 7x -7

if you're trying to solve for x, then look below

7x=7

x=1

4 0
3 years ago
Graph the system of equations. Then determine whether the system has no solution, one solution, or infinitely many solutions. If
natima [27]

Answer:

  d)  one solution; (4, 1)

Step-by-step explanation:

It often works well to follow problem directions. A graph is attached, showing the one solution to be (4, 1).

_____

You know there will be one solution because the lines have different slopes. Each is in the form ...

  y = mx + b

where m is the slope and b is the y-intercept.

The first line has slope -1 and y-intercept +5; the second line has slope 1 and y-intercept -3. The slope is the number of units of "rise" for each unit of "run", so it can be convenient to graph these by starting at the y-intercept and plotting points with those rise and run from the point you know.

6 0
4 years ago
Which triangles must be congruent
Alex17521 [72]
All three triangles are congruent by SAS
6 0
4 years ago
Find the least common denominator between the two fractions. and 2 12 6
SSSSS [86.1K]

The least common denominator is 2

5 0
3 years ago
Find the area of a plane figure bounded by lines
natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6   ⇒   x² + x - 2 = 0   ⇒   (x + 2)(x - 1) = 0   ⇒   x = -2, x = 1

Now, integrate from x = -2 to x = 1

\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,    <em>the bottom of the integral is -2 </em>

= \int\limits^1_2 {x+6-x^{2}-2x-4 } \,

= \int\limits^1_2 {-x^{2}-x+2 } \,  

= \frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,

= (\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))

= (\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)

= \frac{-9}{3} + \frac{3}{2} +6

= -3 + 1.5 + 6

= 4.5


3 0
3 years ago
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