The reflection of any point across the x axis is the symmetric of this point, having x axis as axe of symmetry
Let :
A(1,3) its symmetric vs. x axis is A'(1,-3)
B(-1,5) its symmetric vs. x axis is B'(-1,-5)
C(-3,-3) its symmetric vs. x axis is C'(-3,3)
D(-4,-4) its symmetric vs. x axis is D'(-4,4)
Symmetry vs. the x axis keeps abscises the same & change just the sign of y value
Answer:C 14 1/2
Step-by-step explanation: It is easy just add
1 -) ( 5 sin ø - 3 cos Ø )
________________
sin Ø + 2 cos Ø
← <u>SOLUTION</u><u>→</u>
( 5 sin ø - 3 cos Ø )
________________
sin Ø + 2 cos Ø
=> 5 - 3 cot ∅
( ___________ )
1 + 2 cot ∅
=>. 5 - 3 × 4
[ ____. ]
5
________________
1 + 2 x 4
__
5
= 25 - 12
________. (:. cot Ø = 4 / 5
5 + 8
= 13
___
13
= 1
2 - ) ( b sin Ø - a cos Ø)
_______________
b sin Ø+ a cos Ø
SOLUTION
( b sin Ø - a cos Ø)
_______________
b sin Ø+ a cos Ø
= ( b tan Ø - a )
____________
( b tan Ø+ a )
b
= b × ___ - a
a
__________. (:. tan Ø= b /a
b
b × ___. + a
a
= b ² - a ²
________
b² + a ²
Answer:
b=4
Step-by-step explanation:
4b+5=1+5b (subtract 4b on both sides to get the b's together)
-4b -4b
5=1+5b-4b (subtract 1 from both sides)
-1 -1
4=1b (divide by 1)
b=4