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yanalaym [24]
3 years ago
13

Rotation about the origin

Mathematics
1 answer:
Naily [24]3 years ago
8 0

Answer:

Neither A or B

Step-by-step explanation:

Rotation -90 is counter clockwise direction or turning left. 90 degrees places the figure from quadrant 1 & 4 into quadrant 2 & 1. This means point Q (2,1) rotates to Q' (-1,2). Point P (4,1) rotates to P' (-1,4). Point R (3,2) rotates to R' (2,3).

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What is the slope of the line?
riadik2000 [5.3K]

Answer:

The slope of the line must be 3

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

step 1

we know that

The volume of a rectangular prism is equal to

V_r_p=Bh ----> equation A

where

B is the area of the base of the prism

h is the height of the rectangular prism

step 2

The volume of a square pyramid is equal to

V_s_p=\frac{1}{3}Bh -----> equation B

where

B is the area of the square base of pyramid

h is the height of the pyramid

step 3

substitute equation A in equation B

V_s_p=\frac{1}{3}V_r_p

Find the relationship between the volume of  a rectangular prism and the volume of a square pyramid

\frac{V_r_p}{V_s_p}=3

therefore

The slope of the line must be 3

let's check it

To solve for the slope of the line, you must choose two coordinates first and use the formula

m=\frac{y2-y1}{x2-x1}

Choosing the points (2,6) and (3,9)

substitute

m=\frac{9-6}{3-2}=3 ----> is correct

8 0
3 years ago
Adult tickets to the fall play cost $6 and student tickets cost $3. The drama class sold 25 more student tickets than adult tick
svlad2 [7]

9514 1404 393

Answer:

  • 90 student tickets
  • 65 adult tickets

Step-by-step explanation:

For many "mixture" problems, it is convenient to use a variable for the quantity of the highest contributor. Here, we can use 'a' to represent the number of adult tickets, because adult tickets cost the most. Then the number of student tickets is (a+25), and the total revenue is ...

  6a +3(a+25) = 660

  9a +75 = 660

  9a = 585

  a = 65

  (a+25) = 90

The drama class sold 90 student tickets and 65 adult tickets.

6 0
3 years ago
Suppose <img src="https://tex.z-dn.net/?f=m" id="TexFormula1" title="m" alt="m" align="absmiddle" class="latex-formula"> men and
ollegr [7]

Firstly, we'll fix the postions where the n women will be. We have n! forms to do that. So, we'll obtain a row like:

\underbrace{\underline{~~~}}_{x_2}W_2 \underbrace{\underline{~~~}}_{x_3}W_3 \underbrace{\underline{~~~}}_{x_4}... \underbrace{\underline{~~~}}_{x_n}W_n \underbrace{\underline{~~~}}_{x_{n+1}}

The n+1 spaces represented by the underline positions will receive the men of the row. Then,

x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m~~~(i)

Since there is no women sitting together, we must write that x_2,x_3,...,x_{n-1},x_n\ge1. It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:

\begin{cases}x_2=x_2'+1\\x_3=x_3'+1\\...\\x_{n-1}=x_{n-1}'+1\\x_n=x_n'+1\end{cases}

The equation (i) can be rewritten as:

x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m\\\\&#10;x_1+(x_2'+1)+(x_3'+1)+...+(x_{n-1}'+1)+x_n+x_{n+1}=m\\\\&#10;x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-(n-1)\\\\&#10;x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-n+1~~~(ii)

We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: \dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}

[I can write the proof if you want]

Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: m!

Multiplying all results:

n!\times\dfrac{(m+1)!}{n!(m-n+1)!}\times m!\\\\&#10;\boxed{\boxed{\dfrac{m!(m+1)!}{(m-n+1)!}}}

4 0
3 years ago
Which of these relations is a function?
alisha [4.7K]
The last one (-1,0) (2, 15) (20)
7 0
3 years ago
Read 2 more answers
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sladkih [1.3K]

Answer:D

Step-by-step explanation: 9,14 and 9,4 is equal

3 0
3 years ago
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