Answer:
Cube=150cm^2
Triangular Prism=228ft^2
Step-by-step explanation:
Cube

Triangular prism
Using these formulas

Solving for A

Answer:
D) -0.87
Step-by-step explanation:
I took this test don't quote me on the answer but this is what my peers put.
Answer:
b
Step-by-step explanation:
YES WICH IS BASICLY 2
Answer:
C) 
Step-by-step explanation:
Line of best fit (trendline) : a line through a scatter plot of data points that best expresses the relationship between those points.
All the given options for the line of best fit are linear equations.
Therefore, we can add the line of best fit to the graph (see attached), remembering to have roughly the same number of points above and below the line.
Linear equation: 
(where
is the slope and
is the y-intercept)
From inspection of the line of best fit, we can see that the y-intercept (where x = 0) is approximately 8. So this suggests that options C or D are the solution.
We can also see that the slope (gradient) of the line of best fit is approximately -0.5 (as the rate of change (y/x) is -1 unit of y for every +2 units of x).
Therefore, C is the solution, and the closet approximation to the line of best fit is 
Answer:
b) 95 percent confidence interval for this single-sample t test
[11.64, 16.36]
Step-by-step explanation:
Explanation:-
Given data a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.
Sample size 'n' =62
sample mean x⁻ = 14
sample standard deviation 'S' = 9.3
<u>95 percent confidence interval for this single-sample t test</u>
The values are
the <u>95 percent confidence interval for the population mean 'μ'</u>
Degrees of freedom γ=n-1=62-1=61
t₀.₀₅ = 1.9996 at 61 degrees of freedom

(14-2.361 , 14 + 2.361)
[(11.64 , 16.36]
<u>Conclusion:-</u>
95 percent confidence interval for this single-sample t test
[11.64, 16.36]
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