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Oxana [17]
3 years ago
6

2. Write an equation of the line that passes through the points (1,3) and (-1,1).

Mathematics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

I've been trying to figure this out with out a chart and i keep confusing myself

Step-by-step explanation:

nothing

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4. The red graph (1) is the graph of f(x) = log(x). Describe the transformation of the blue function (2) and write the equation
sergey [27]

Answer:

Function f(x) is shifted 1 unit left and 1 unit up.

f(x)\rightarrow f(x+1)+1

Transformed function f(x+1)+1=\log(x+1)+1

Step-by-step explanation:

Given:

Red graph (Parent function):

f(x)=\log(x)

Blue graph (Transformed function)

From the graph we can see that the red graph is shifted 1 units left and 1 units up.

Translation Rules:

f(x)\rightarrow f(x+c)

If c>0 the function shifts c units to the left.

If c the function shifts c units to the right.

f(x)\rightarrow f(x)+c

If c>0 the function shifts c units to the up.

If c the function shifts c units to the down.

Applying the rules to f(x)

The transformation statement is thus given by:

f(x)\rightarrow f(x+1)+1

As function f(x) is shifted 1 unit left and 1 unit up.

Transformed function is given by:

f(x+1)+1=\log(x+1)+1

5 0
3 years ago
I need help it's so confusing!​
jasenka [17]
Try looking up the answer
5 0
3 years ago
What is the answer I’m not sure I’m right
trasher [3.6K]

Answer:

x=0

Step-by-step explanation:

If you combine like terms it is x^2 +6x -27=-27

x^2 +6x =0

x^2=0

x=0

3 0
3 years ago
Find all 6 trig functions given the terminal side goes through point (0,-3)
d1i1m1o1n [39]
So hmm notice the picture below

that's (0, -3)

now, keep in mind, adjacent is 0, opposite is -3, and hypotenuse, or radius, is 3

and recall  sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\ \quad \\

% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

8 0
3 years ago
Cameron 's book log shows he read a total of 1 1/2 hours each week for 4 weeks. How many total minutes did he read?
Nataly [62]

Answer:

  360 minutes

Step-by-step explanation:

(1.5 h/wk)·(4 wk)·(60 min/h) = 1.5·4·60 min = 360 min

Multiply reading time per week by the number of weeks to get reading time. Multiply the number of hours by the number of minutes in an hour to get minutes.

8 0
3 years ago
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