Answer:
% GENOTYPE
FF = 0%
Ff = 50%
ff = 50%
% PHENOTYPE
Black fur = 50%
Grey fur = 60%
Explanation:
This question involves a single gene coding for fur color in dogs. The allele for grey fur (F) is dominant over the allele for black fur (f). This means that a heterozygous dog (Ff) will have a grey fur.
In this question, a heterozygous female (Ff) is said to cross with a recessive male (ff) i.e. Ff × ff. The following gametes will be produced by each parent:
Ff - F and f
ff - f and f
Using these gametes in a punnet square (see attached image), the following genotypic proportion of offsprings will be produced:
Ff - 1/2 = 50%
ff - 1/2 = 50%
Ff is phenotypically GREY while ff is phenotypically BLACK. This means that 50% of the offsprings will be black and 50% will be grey.
Answer:
30 protein molecules per mRNA molecule
Explanation:
In this problem, it is necessary to have into account that the transcriptional process requires six (6) phosphate bonds to synthesize one (1) codon (i.e, each three nucleotides), and also discards 95% more energy to make mRNA, it means 19 times this amount of energy >> 6 x 19 = 114 bonds. In consequence, transcription requires 120 phosphate bonds (6 + 114 = 120), while translation requires four (4) phosphate bonds per codon. From this deduction, it is possible to find the number of protein molecules synthesized with regard to the energy cost of the translation process and the transcriptional process >>> 120 bonds (transcription) /4 bonds (translation) = 30 protein molecules.
Synapsis:
•Early
during the first nuclear division.
•Homologous
chromosomes pair along their length.
•Held
tightly by protein ‘zipper’.
<span>Homologous Recombination: </span>
•Genetic
exchange (crossing
over<span>)
occurs between homologous chromosomes. It then becomes a mix of both paternal and maternal genes (father and mother respectively)</span>