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erica [24]
3 years ago
5

Find the volume of this square based pyramid. 5 cm 5 cm 5 cm. Round to the nearest tenth.

Mathematics
1 answer:
vodka [1.7K]3 years ago
4 0

Answer:

41.666 cm³ or 41.7 cm³  rounded to the nearest tenth.

Step-by-step explanation:

Volume of a square pyramid = base length² × height ÷ 3

25 × 5/3 = 41. 666

Have a great day:)

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Write the following number in standard decimal form.<br> one and eighty-five hundredths
sergejj [24]

Answer:

1.85

Step-by-step explanation:

0ne (1) and Eighty - five hundredths (0.85)

Hope this helps

Mark Brainliest!

7 0
3 years ago
Read 2 more answers
What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Radda [10]

Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± \sqrt{-1} = ± i ( noting that \sqrt{-1} = i ), and

x² = - 5 ( take the square root of both sides )

x = ± \sqrt{-5} = ± \sqrt{5(-1)} = ± \sqrt{5} × \sqrt{-1} = ± i\sqrt{5}

Solutions are x = ± i and x = ± i\sqrt{5}

3 0
3 years ago
#8 What is the VALUE of point B (put in decimal form) *
MakcuM [25]

Answer:

B= -2.75

A= -0.25

C= 2.50

4 0
3 years ago
Grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height. how high
bezimeni [28]

Given that grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height.

So if D is the diameter and h is the height of the conical pile then we can write:


D=3h

We know that diameter = 2r, where r is the radius

2r=3h

r=\frac{3h}{2}

Volume of conical pile is given by formula

V=\frac{1}{3}\pi r^2h

Given that volume is 1110 cubic feet.

Now plug the values of Volume and r into equation of volume

1110=\frac{1}{3}\pi (\frac{3h}{2})^2h

1110=\frac{1}{3}\pi\cdot\frac{9h^2}{4}\cdot h

1110=\pi\cdot\frac{3h^3}{4}

1110\cdot\frac{4}{3\pi}=h^3

471.098631552=h^3

take cube root of both sides

7.78103342467=h

Hence height is approx 7.78 feet.

7 0
3 years ago
Suppose that x has a binomial distribution with n = 201 and p = 0.45. (Round np and n(1-p) answers to 2 decimal places. Round yo
ycow [4]

Answer:

a) It can be used because np and n(1-p) are both greater than 5.

Step-by-step explanation:

Binomial distribution and approximation to the normal:

The binomial distribution has two parameters:

n, which is the number of trials.

p, which is the probability of a success on a single trial.

If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.

In this question:

n = 201, p = 0.45

So, lets verify the conditions:

np = 201*0.45 = 90.45 > 5

n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5

Since both np and n(1-p) are greater than 5, the approximation can be used.

3 0
3 years ago
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