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oee [108]
3 years ago
6

\begin{aligned} &y=2x -1 \\\\ &5x-4y=1 \end{aligned} ​ y=2x−1 5x−4y=1 ​ Is (1,1)(1,1)left parenthesis, 1, comma, 1, righ

t parenthesis a solution of the system?
Mathematics
1 answer:
iVinArrow [24]3 years ago
5 0

Answer:

Therefore, ( 1 , 1 ) is the Solution to the Given Equations

y=2x-1  

5x-4y=1

Step-by-step explanation:

Given:

y=2x-1   ..............Equation ( 1 )

5x-4y=1 ..............Equation ( 2 )

To Find:

x = ?

y = ?

Solution:

y=2x-1   ..............Equation ( 1 )

5x-4y=1 ..............Equation ( 2 )

Substituting equation 1 in equation 2 we get

5x-4(2x-1)=1\\applying\ distributive\ property\ we\ get\\5x-8x+4=1\\\\-3x=1-4=-3\\\\x=\frac{-3}{-3}=1\\ \therefore x = 1\\

Substituting 'x' in Equation ( 1 ) we get

y=2\times 1-1\\\\y=1\\\\\therefore y =1\\

Therefore, ( 1 , 1 ) is the Solution to the Given Equations

y=2x-1  

5x-4y=1

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A spherical balloon is inflated so that its volume is increasing at the rate of 3 ft3/min. How fast is the diameter of the ballo
beks73 [17]

When an spherical balloon volume is increasing at the rate of 3ft^3/min then the diameter of the balloon is increasing \frac{3}{2\pi }ft /min

How can we find the rate of change of balloon's diameter ?

The volume of a spherical balloon is v=\frac{4}{3} \pi r^3

In form of diameter we can write as

v=\frac{4}{3} \pi (\frac{D}{2} )^3\\=\frac{1}{6} \pi D^3

Now we will differentiate both sides wrt to t we get

\frac{dv}{dt} =\frac{1}{6} \pi 3D^2 \frac{dD}{dt} \\\frac{dD}{dt} =\frac{2}{\pi D^2} \frac{dv}{dt} \\\\when r=1\\D=2ft

Given in the question \frac{dv}{dt} =3ft^3/min

thus when we substitute the values we get

\frac{dD}{dt} =\frac{2}{\pi *2^2} (3)\\\frac{dD}{dt}=\frac{3}{2\pi }  ft/min

Learn more about the differentiation here:

brainly.com/question/28046488

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3 0
2 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

     -6 + (3*t) =  7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

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3 years ago
Find the length of the side
MrRa [10]

Answer:

So AC = 25

Step-by-step explanation:

ABC = LMN

That means AB = LM

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                    AC = LN

We know AB = 41  MN = 38  and LN  = 25

AB = LM = 41

BC = MN=38

AC = LN=25

So AC = 25

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Answer:

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Step-by-step explanation:

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