Answer: 19
Step-by-step explanation:
I do it when the numbers are to big but that's me
X intercept is 4/3 because you plug zeros in for y to find the y intercept
Given: y = 2x^2 - 32x + 56
1) y = 2 [ x^2 - 16x] + 56
2) y = 2 [ (x - 8)^2 - 64 ] + 56
3) y = 2 (x - 8)^2 - 128 + 56
4) y = 2 (x - 8)^2 - 72 <----------- answer
Minimum = vertex = (h,k) = (8, - 72)
=> x-ccordinate of the minimum = 8 <-------- answer
