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3 years ago

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Convert 0.5 lbs to grams

1 answer:

Luda [366]3 years ago

3 0

Answer:

226.796

Step-by-step explanation:

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Luke can build 2 tables in a day, and he has to build more than 18 wooden tables for a client. If he works for x days, what is t

kodGreya [7K]

The answer to the question is b

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4 years ago

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What is the value of x?<br><br> 2<br> 3<br> 6<br> 7

Romashka-Z-Leto [24]

Answer:

x = 2

Step-by-step explanation:

By the property of intersecting chords outside of the circle.

$EC \times ED = EB \times EA \\ (x + 4)(x + 4 + 1) = (x + 1)(x + 1 + 11) \\ (x + 4)(x + 5) = (x + 1)(x + 12) \\ {x}^{2} + (4 + 5)x + 20 = {x}^{2} + (1 + 12)x + 12 \\ 9x + 20 = 13x + 12 \\ 9x - 13x = 12 - 20 \\ - 4x = - 8 \\ x = \frac{ - 8}{ - 4} \\ \huge \red{ \boxed{x = 2}}$

7 0

3 years ago

Read 2 more answers

40, 10, 5/2 5/8... (fractions) is it arithmetic or geometric and what are the next two terms PLZ HELP DUE IN 10 MINS

patriot [66]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

$40,\:10,\:\frac{5}{2},\:\frac{5}{8}$

A geometric sequence has a constant ratio 'r' and is defined by

$\:a_n=a_0\cdot r^{n-1}$

Computing the ratios of all the adjacent terms

$\frac{10}{40}=\frac{1}{4},\:\quad \frac{\frac{5}{2}}{10}=\frac{1}{4},\:\quad \frac{\frac{5}{8}}{\frac{5}{2}}=\frac{1}{4}$

The ratio of all the adjacent terms is the same and equal to

$r=\frac{1}{4}$

Thus, the given sequence is a geometric sequence.

As the first element of the sequence is

$a_1=40$

Therefore, the nth term is calculated as

$\:a_n=a_0\cdot r^{n-1}$

$a_n=40\left(\frac{1}{4}\right)^{n-1}$

Put n = 5 to find the next term

$a_5=40\left(\frac{1}{4}\right)^{5-1}$

$a_5=40\cdot \frac{1}{4^4}$

$a_5=\frac{40}{4^4}$

$=\frac{2^3\cdot \:5}{2^8}$

$a_5=\frac{5}{2^5}$

$a_5=\frac{5}{32}$

now, Put n = 6 to find the 6th term

$a_6=40\left(\frac{1}{4}\right)^{6-1}$

$a_6=40\cdot \frac{1}{4^5}$

$a_6=\frac{40}{4^5}$

$=\frac{2^3\cdot \:5}{2^{10}}$

$a_6=\frac{5}{2^7}$

$a_6=\frac{5}{128}$

Thus, the next two terms of the sequence 40, 10, 5/2, 5/8... is:

$a_5=\frac{5}{32}$

$a_6=\frac{5}{128}$

7 0

3 years ago

Need help again. Please explain your answer.

Elis [28]

4y + 3 ≤ y + 6

4y + 3 - 3 ≤ y + 6 - 3

4y ≤ y + 3

4y - y ≤ y - y + 3

3y ≤ 3

3y/3 ≤ 3/3

y ≤ 1

So any value of y less than or equal to 1 (so 1 is included in the solution set) satisfies the inequality. C is the correct answer.

5 0

3 years ago

What is a reasonable estimate for the solution? O (1,-3/4) O (-3/4,1) O (-1,3/4) O (3/4,-1)

Zina [86]

Answer:

See Explanation

Step-by-step explanation:

Your question is incomplete, as the equations or graph or table(s) were not given.

However, I'll give a general way of solving this.

Take for instance, the equations are:

$y = \frac{4}{3}x - 1$

$y = \frac{2}{3}x - \frac{1}{2}$

To do this, we start by equating both equations.

$y = y$

i.e.

$\frac{4}{3}x - 1= \frac{2}{3}x - \frac{1}{2}$

Collect Like Terms

$\frac{4}{3}x - \frac{2}{3}x= 1 - \frac{1}{2}$

Take LCM

$\frac{4x- 2x}{3}= \frac{2 - 1}{2}$

$\frac{2x}{3}= \frac{1}{2}$

Cross Multiply

$2x * 2 = 3 * 1$

$4x = 3$

Make x the subject

$x = \frac{3}{4}$

Substitute 3/4 for x in $y = \frac{4}{3}x - 1$

$y = \frac{4}{3} * \frac{3}{4} - 1$

$y = 1 - 1$

$y = 0$

Hence:

$(x,y) = (\frac{3}{4},0)$

6 0

3 years ago