What is the relationship of tissues to cells?

Are protons and electrons the same number

enot [183]

Atoms must have equal numbers of protons and electrons. So to answer your question, yes protons and electrons are the same number.

4 0

4 years ago

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In the preindustrial era, settlements were more likely to be near sources of surface water than in the industrial era.

Ksenya-84 [330]

True that in the preindustrial era, settlements were more likely to be near sources of surface water than in the industrial era. The main reason being that during the preindustrial era people were dependent mostly on irrigation. For irrigation people were dependent on surface water. This was the main and basic reason.

7 0

3 years ago

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** 2. Where are each of the three particles located within the atom?

dedylja [7]

Answer:

protons and neutrons located within the nucleus, with electrons in orbitals surrounding the nucleus.

5 0

3 years ago

The following is the balanced equation of the combustion of methane gas with oxygen gas:

tangare [24]

Answer:

The correct option is: C. 1.1 L

Explanation:

Given: Temperature: T = 25°C = 25 +273 = 298K (∵ 1°C = 273K)

Pressure: P = 1 atm, Given mass of- CH₄: m₁ = 1g; O₂: m₂ = 3g

Volume: V= ?

Molar mass of CH₄: M₁ = 16g; O₂: M₂ = 32g

As Number of moles: $n = \frac{given\: mass (m)}{molar\: mass (M)}$

∴ Number of moles of CH₄: $n_{1} = \frac{m_{1}}{M_{1}} = \frac{1 g}{16 g} = 0.0625 mol$

Number of moles of O₂: $n_{2} =\frac {m_{2}}{M_{2}} = \frac{3 g}{32 g} = 0.0937 mol$

In the given reaction: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)

1 mole of methane (CH₄) reacts with 2 moles oxygen (O₂) to give 1 mole of CO₂.

So 0.0625 mol of CH₄ reacts with $\frac{2 \times 0.0625}{1} = 0.125 mol \: O_{2}$ .

Thus the limiting reagent is O₂.

Now, 2 moles O₂ gives 1 mole of CO₂

So 0.0937 mol O₂ gives $\frac{1 \times 0.0937}{2} = 0.0468 mol \:CO_{2}$

Therefore, the total number of moles of gas after the completion of the reaction: n = number of moles of CO₂: n₃ = 0.0468 mol

Now to calculate the volume of the balloon, we use the ideal gas law: $PV =nRT$

$\Rightarrow V = \frac{nRT}{P}$

Here, R is the gas constant = 0.08206 L·atm/(mol·K)

T is Temperature,

P is Pressure,

n is Total number of moles of gas

and, V is Volume

Therefore, the volume of the balloon after the completion of the reaction:

$V = \frac{n_{3}RT}{P}$

$V = \frac{0.0468 mol \times 0.08206 L.atm/(mol.K) \times 298K}{ 1atm}$

$\Rightarrow V = 1.14 L$

Therefore, the total volume of the balloon after the completion of the reaction: V = 1.14 L

5 0

4 years ago

Two gases with different masses are injected into the opposite ends of a long tube at the same time and allowed to diffuse towar

wariber [46]

Answer:

b) the gases will mix closer to the end that holds the heavier gas.

Explanation:

The question is based on the Graham's law of diffusion.

According to Graham's law of effusion, the rate of effusion of gases is dependent on the density of the gases. Such that the rate of effusion a gas is inversely proportional to the square root of its density.
Therefore, a lighter gas effuses faster compared to a heavier gas.
In this case, the gases will mix closer to the end that holds the heavier gas, because the lighter gas will effuse faster and cover a longer distance compared to the heavier gas.
For instance , if we take two gases ammonia (NH4) and Chlorine (Cl2), if they were allowed to effuse from opposite ends of a long tube, then NH4 would effuse faster since it is lighter than chlorine. Consequently, the two would mix near the end that holds chlorine gas.

4 0

3 years ago