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AlekseyPX
3 years ago
8

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Chemistry
2 answers:
sp2606 [1]3 years ago
8 0

Answer:

YIkES One thing u can do i ask your teacher about it or say that u need help with it the cant make fun of u because u need help with your work.

Makovka662 [10]3 years ago
8 0
We can’t really answer the question because it’s a drawing however, I can only say the coffee she left in the mug was a liquid that became into a solid depending on how long she left the mug in for. After she took it out and it said it was frozen, if she microwaved it for 1-2 minutes the iced coffee will melt due to the heated waves coming out from the microwave, I don’t know if this will help you or not but mainly ask your teacher
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3 years ago
Calculate the freezing point of the solution containing 0.105 m k2s. calculate the boiling point of the solution above. -g
Licemer1 [7]
Quantity of K2S m = 0.105 m 
Number of ions i = 2(K) + 1(S) = 3
 Freezing point depression constant of water Kf = 1.86 
delta T = i x m x Kf = 3 x 0.105 x 1.86 = 0.586
 Freezing point = 0 - 0.586 = 0.586 C
 Boiling point constant of water Kb = 0.512
 delta T = i x m x Kb = 3 x 0.105 x 0.512 = 0.161
 Boiling point = 100 + 0.161 = 100.161 C
5 0
3 years ago
Read 2 more answers
What are the base units the SI units are based on?<br> A-10<br> B-100<br> C-1,000<br> D-1
Olegator [25]

Answer:

A-10

Explanation:

In the SI, designations of multiples and subdivision of any unit may be arrived at by combining with the name of the unit the prefixes deka, hecto, and kilo meaning, respectively, 10, 100, and 1000, and deci, centi, and milli, meaning, respectively, one-tenth, one-hundredth, and one-thousandth.

IM NOT SURE PO

4 0
2 years ago
If you had a bottle that contained 5.69x1024 molecules of water, how many
Valentin [98]
Yeah what the other person said ^
6 0
2 years ago
(I)how many atoms are present in 7g of lithium?
ICE Princess25 [194]

Answer :

(i) The number of atoms present in 7 g of lithium are, 6.07\times 10^{23}

(ii) The number of atoms present in 7 g of lithium are, 1.204\times 10^{24}

(iii) The number of moles of F_2 is, 1 mole

The number of moles of CO_2 is, 0.5 mole

The number of moles of OH^- is, 1 mole

Explanation :

<u>Part (i) :</u>

First we have to calculate the moles of lithium.

\text{Moles of }Li=\frac{\text{Mass of }Li}{\text{Molar mass of }Li}

Molar mass of Li = 6.94 g/mole

\text{Moles of }Li=\frac{7g}{6.94g/mol}=1.008mole

Now we have to calculate the number of atoms present.

As, 1 mole of lithium contains 6.022\times 10^{23} number of atoms

So, 1.008 mole of lithium contains 1.008\times 6.022\times 10^{23}=6.07\times 10^{23} number of atoms

Thus, the number of atoms present in 7 g of lithium are, 6.07\times 10^{23}

<u>Part (ii) :</u>

First we have to calculate the moles of carbon.

\text{Moles of }C=\frac{\text{Mass of }C}{\text{Molar mass of }C}

Molar mass of C = 12 g/mole

\text{Moles of }C=\frac{24g}{12g/mol}=2mole

Now we have to calculate the number of atoms present.

As, 1 mole of carbon contains 6.022\times 10^{23} number of atoms

So, 2 mole of carbon contains 2\times 6.022\times 10^{23}=1.204\times 10^{24} number of atoms

Thus, the number of atoms present in 7 g of lithium are, 1.204\times 10^{24}

<u>Part (iii) :</u>

<u>To calculate the moles of </u>F_2<u> :</u>

\text{Moles of }F_2=\frac{\text{Mass of }F_2}{\text{Molar mass of }F_2}

Molar mass of F_2 = 38 g/mole

\text{Moles of }F_2=\frac{19g}{19g/mol}=1mole

Thus, the number of moles of F_2 is, 1 mole

<u>To calculate the moles of </u>CO_2<u> :</u>

\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}

Molar mass of CO_2 = 44 g/mole

\text{Moles of }CO_2=\frac{22g}{44g/mol}=0.5mole

Thus, the number of moles of CO_2 is, 0.5 mole

<u>To calculate the moles of </u>OH^-<u> ions :</u>

\text{Moles of }OH^-=\frac{\text{Mass of }OH^-}{\text{Molar mass of }OH^-}

Molar mass of OH^- = 17 g/mole

\text{Moles of }OH^-=\frac{17g}{17g/mol}=1mole

Thus, the number of moles of OH^- is, 1 mole

4 0
3 years ago
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