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The line that passes through (-2, 1) and (8, 2) is:
y = (1/10)*x + 12/10
<h3>How to find the equation of the line?</h3>I assume you want to find the equation of the line that passes through (-2, 1) and (8, 2).
A general linear equation is written as:
y = a*x + b
If the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope can be written as:
In this case, we know that it passes through (-2, 1) and (8, 2), then:
Then the line is:
y = (1/10)*x + b
To find the value of b, we use one of the given points, for example if we use (8, 2), it means that when x = 8, we must have y = 2.
2 = (1/10)*8 + b
2 - 8/10 = b
20/10 - 8/10 = b
12/10 = b
Then the linear equation is:
y = (1/10)*x + 12/10
If you want to learn more about linear equations:
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Answer:
Step-by-step explanation:
For this case we can calculate the sample variance and deviation with the following table
Class Midpoint (Xi) fi Xi*fi Xi^2 *fi
120.6-123.6 122.1 17 2075.7 253443
123.7-126.7 125.2 49 6134.8 768077
126.8-129.8 128.3 29 3720.7 477365.8
129.9-132.9 131.4 41 5387.4 707904.4
133.0-136.0 134.5 35 4007.5 633158.8
___________________________________________
Total 171 22026.1 2839948.85
For this case we can calculate the mean or expected value with the following formula:
Now we can calculate the sample variance with the following formula:
And if we replace we got:
And the standard deviation would be the square root of the variance and we got: