All categories

3 years ago

A computer company wants to determine the proportion of defective computer chips from a day's production. A

Mathematics

1 answer:

ozzi3 years ago

5 0

Answer:

0.12 ± 1.96 * √(0.12(0.88) / 100)

Step-by-step explanation:

Confidence interval :

Phat ± Zcritical * √(phat(1 -phat) / n)

Phat = 12/100 = 0.12

1 - phat = 0.88

Zcritical at 95% = 1.96

Hence, we have :

0.12 ± 1.96 * √(0.12(0.88) / 100)

0.12 ± 1.96 * 0.0324961

0.12 ± 0.0636924

Lower boundary = (0.12 - 0.0636924) = 0.0563

Upper boundary = 0.12 + 0.0636924 = 0.1837

You might be interested in

Need help!!<br> will give brainlist

prisoha [69]

White, 7/10= 14/20
It has the largest chance of being selected at random

5 0

3 years ago

jamal is making pancakes. He has 6 3/4 cups of batter, but he needs a total of 12 cups. How much more batter does Jamal need?

vampirchik [111]

Jamil has already 6 3/4 cups of butter.
He need 12. SO in order to get the needed butter, we subtract 6 3/4 to 12.

= 12 - 6 3/4
= 11 4/4 - 6 3/4
= 5 1/4

So Jamil needs 5 1/4 cups of butter to achieve the 12 cups.

8 0

3 years ago

Triangle PQR has two known interior angles of 24°, and 100°.

Tamiku [17]

180-24=5
180-56=34
Both are equal
D

3 0

3 years ago

Read 2 more answers

A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a

kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, $s=\frac{dx}{dt}=470\ mi/h$

Now, applying Pythagoras theorem to the triangle, we have:

$D^2=h^2+x^2\\\\D^2=1+x^2$

Differentiating with respect to time 't', we get:

$2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)$

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

$2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi$

Now, plug in all the given values and solve for $\frac{dD}{dt}$ . This gives,

$\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h$

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

6 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

mrs_skeptik [129]

2(2x − 1) > 6 or x + 3 ≤ −6

2(2x − 1) > 6

4x - 2 > 6

4x > 8

x > 2

x + 3 ≤ −6

x ≤ - 9

Solution: x ≤ - 9 or x > 2

(- ∞ , - 9] or (2 , + ∞)

Answer is the first one

(- ∞ , - 9] or (2 , + ∞)

8 0

3 years ago