A computer company wants to determine the proportion of defective computer chips from a day's production. A

Mathematics

1 answer:

ozzi3 years ago

5 0

Answer:

0.12 ± 1.96 * √(0.12(0.88) / 100)

Step-by-step explanation:

Confidence interval :

Phat ± Zcritical * √(phat(1 -phat) / n)

Phat = 12/100 = 0.12

1 - phat = 0.88

Zcritical at 95% = 1.96

Hence, we have :

0.12 ± 1.96 * √(0.12(0.88) / 100)

0.12 ± 1.96 * 0.0324961

0.12 ± 0.0636924

Lower boundary = (0.12 - 0.0636924) = 0.0563

Upper boundary = 0.12 + 0.0636924 = 0.1837

You might be interested in

Andy Dixon bought 3 paintbrushes for $1.75 each and 7 tubes of oil paint for $2.49 each.how much did he spend in all?

AnnZ [28]

The answer would be $22.68!

If Andy bought 3 paintbrushes for $1.75 each, then we just multiply how much they cost by the number that the bought.

1.75 x 3 = 5.25

If Andy bought 7 tubes of oil paint, we just do the same thing we did in the first step! Multiply how much they cost by the number that the bought.

2.49 x 7 = 17.43

5 0

4 years ago

Read 2 more answers

Turner is deep-sea diving with two friends. Janelle is floating on the surface 15 meters above

lutik1710 [3]

23 because if u add bothe of them up

3 0

3 years ago

How many are 7 raised to 2 ???

Stolb23 [73]

Answer:

$\huge \boxed{49}$