Question

A computer company wants to determine the proportion of defective computer chips from a day's production. A

Answer 1

Answer:

0.12 ± 1.96 * √(0.12(0.88) / 100)

Step-by-step explanation:

Confidence interval :

Phat ± Zcritical * √(phat(1 -phat) / n)

Phat = 12/100 = 0.12

1 - phat = 0.88

Zcritical at 95% = 1.96

Hence, we have :

0.12 ± 1.96 * √(0.12(0.88) / 100)

0.12 ± 1.96 * 0.0324961

0.12 ± 0.0636924

Lower boundary = (0.12 - 0.0636924) = 0.0563

Upper boundary = 0.12 + 0.0636924 = 0.1837