A computer company wants to determine the proportion of defective computer chips from a day's production. A
1 answer:
Answer:
0.12 ± 1.96 * √(0.12(0.88) / 100)
Step-by-step explanation:
Confidence interval :
Phat ± Zcritical * √(phat(1 -phat) / n)
Phat = 12/100 = 0.12
1 - phat = 0.88
Zcritical at 95% = 1.96
Hence, we have :
0.12 ± 1.96 * √(0.12(0.88) / 100)
0.12 ± 1.96 * 0.0324961
0.12 ± 0.0636924
Lower boundary = (0.12 - 0.0636924) = 0.0563
Upper boundary = 0.12 + 0.0636924 = 0.1837
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The answer is .036 hope it helps
5.4 cm on map represents 270 m
5.4 cm on map represents 27000 cm
1 cm on map represents 27000/5.4 = 5000 cm
= 50m
Answer:
c
Step-by-step explanation:
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7 hours ago I gave you the answer on this question, my dear!!
Answer:
Its d or option 4
Step-by-step explanation:
A 2-column table with 4 rows. Column 1 is labeled x with entries 2, 4, 6, 8. Column 2 is labeled y with entries negative 4, negative 12, negative 20, negative 28. Hope this helps :)
