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skelet666 [1.2K]
4 years ago
15

Which best defines a circle?

Mathematics
1 answer:
Paraphin [41]4 years ago
6 0
I believe the correct answer is A, 

You might be interested in
1. Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary.
gtnhenbr [62]
1. First, we are going to draw our triangle (picture 1). Next, we are going to use the cosine rule to find the length of side b:
b^2=a^2+c^2-2accosA
b= \sqrt{a^2+c^2-2accosA}
b= \sqrt{14^2+20^2-2(14)(20)cos(74)}
b=21.02
Now that we have all the sides of the triangle, we use Heron's formula to find its area. But first we need to find the semi-perimeter of the triangle. To do it, we are going to use the formula: s= \frac{a+b+c}{2}
where 
s is the semi-perimeter.
a, b, and c are the sides of the triangle. 

s= \frac{14+21.02+20}{2}
s= \frac{54.02}{2}
s=27.51

Now, we can use Heron's formula: A= \sqrt{s(s-a)(s-b)(s-c)}
where
A is the area of the triangle.
s is the semi-perimeter of the triangle.
a, b, and c are the sides of the triangle.
A= \sqrt{27.51(27.51-14)(27.51-21.02)(27.51-20}
A=134.59cm^2

The area of the triangle ABC is 134.59 square centimeters. We can conclude that the correct answer of your given choices is: 134.58 cm2 (your teacher made a little rounding error)

2. Just like before, the first thing we are going to do is draw the triangle (picture 2). Next, we are going to use the cosine rule to find the length of side b:
b= \sqrt{a^2+c^2-2accosA}
b= \sqrt{11^2+18^2-2(11)(18)cos(71)}
b=17.78

Semi-perimeter:
s= \frac{a+b+c}{2}
s= \frac{11+17.78+18}{2}
s=23.39

Heron's formula:
A= \sqrt{s(s-a)(s-b)(s-c)}
A= \sqrt{23.39(23.39-11)(23.39-17.78)(23.39-18)}
A=93.61cm^2

The area of triangle ABC is 93.61 square centimeters. We can conclude that the correct answer is <span>93.61 cm2

3. We have the vectors </span><span>P = (-5, 5) and Q = (-13, 6), and we want to find the vector 2 times PQ; in other words, we want to find the result of the multiplication between the vector initiating at P and ending at Q and the scalar 2.
First we are going to find the components of the vector </span>P and ending at Q:
PQ=\ \textless \ -13-(-5), 6-5\ \textgreater \
PQ=\ \textless \ -13+5, 1\ \textgreater \
PQ=\ \textless \ -8,1\ \textgreater \

Next, we are going to multiply the vector by the scalar 2:
2PQ=2\ \textless \ -8,1\ \textgreater \
2PQ=\ \textless \ -16,2\ \textgreater \

Now, we can find the magnitude of the vector. Remember that the magnitude of a vector is given by the Pythagorean theorem: |a|= \sqrt{x^2+y^2}
where
|a| is the magnitude of the vector 
\ \textless \ x,y\ \textgreater \ are the components of the vector.

We know that the components of the vector are x=-16 and y=2, so lets replace those vales in our equation: 
|2PQ|= \sqrt{-16^2+2^2}
|2PQ|= \sqrt{-16^2+2^2}
|2PQ|= \sqrt{256+4}
|2PQ|= \sqrt{260}

We can conclude that the correct answer is: <span><-16, 2>, square root of two hundred and sixty.</span><span>
</span>

4 0
4 years ago
This is my last question please help​
Lesechka [4]

Answer:

first was the answer

(2tanA/2)/(1+tan^2A/2)

5 0
2 years ago
Solve for a. a+(−1.3)=−4.5 Enter your answer in the box.
Ivahew [28]
Add 1.3 to each side and get a = -3.2
6 0
3 years ago
Read 2 more answers
The larger of two numbers is 8 more than four times the smaller. If the larger is increased by four times the smaller, the resul
olganol [36]
So let’s make the smaller number x and the larger one y....

Set up your equation by following the words signaling mathematical operations from the question.

y = 8 + 4x
y + 4x = 40

Now let’s bring all variables to one side and solve the system if equations with elimination...

y - 4x = 8
y + 4x = 40

Add the equations:

2y = 48
y = 24

Plug the y-value into one of the original equations:

24 = 8 + 4x
16 = 4x
4x = 16
x = 4

And there you have it! The smaller number [x] is 4 and the larger number [y] is 24.
7 0
3 years ago
PLEASE HELP IS LINEAR INEQUALITIES !!
SashulF [63]

Answer:

THE ANSWER IS C

Step-by-step explanation:

BECAUSE BABABOOEEE

8 0
3 years ago
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