Equation of the perpendicular
y= 2x+6
slope of the perpendicular = 2
slope of the req. line = -1/2
equation of the req. line
y - y1 = m(x - x1)
y - 2 = -1/2(x + 4)
2(y - 2) = -1(x + 4)
2y - 4 = -x - 4
2y = -x
y = (-1/2)x
this is your req. equation of line.
Answer:





Step-by-step explanation:
According to the Order of Operations [GEMS\BOMDAS\PEMDAS etc.], you evaluate everything in parentheses first before preceding with your Division & Multiplication and Subtraction & Addition. When you do this, you will know exactly which expression corresponds with its Distributive Property expression.
I am joyous to assist you anytime.
Answer:
y + 3 = 2(x + 1)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = 2 and (a, b) = (- 1, - 3), thus
y - (- 3) = 2(x - (- 1)), that is
y + 3 = 2(x + 1)
Answer:
I hope that this can help you