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Serggg [28]
3 years ago
13

What type of association does the following scatter plot represent?

Mathematics
1 answer:
vodomira [7]3 years ago
4 0
2)Negative linear association because the line is straight and it’s going down meaning it’s negative
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What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
polet [3.4K]
The two angles are the same value. To find, think of the equation 3<em>x</em>+50=6<em>x</em>-10. Put the 6<em>x</em> to the other side of the equation. You shall get -3x+50=-10. Move the 50 to the other side, and you'll end up with -3<em>x</em>=-60. Divide each number by -3 to find <em>x</em> now. Your final answer will be <em>x=20</em>.

Answer: <em>x=20</em>
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3 years ago
Electricity bills: According to a government energy agency, the mean monthly household electricity bill in the United States in
liberstina [14]

The 9th percentile of the bill amounts is 81.0634.

<h3>How to calculate the percentile?</h3>

Population mean, µ = 110.56

Population standard deviation, σ = 22

a) p = 0.09

Z score at p = 0.09 using excel = NORM.S.INV(0.09) = -1.3408

Value of X = µ + z*σ = 110.56 + (-1.3408)*22 = 81.0634

9th percentile = 81.0634

b) p = 0.66

Z score at p = 0.66 using excel = NORM.S.INV(0.66) = 0.4125

Value of X = µ + z*σ = 110.56 + (0.4125)*22 = 119.6342

66th percentile = 119.6342

c) Median = 0.50

Z score at p = 0.5 using excel = NORM.S.INV(0.5) = 0

Value of X = µ + z*σ = 110.56 + (0)*22 = 110.56

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Learn more about percentile on:

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5 0
2 years ago
What is 27 quarters. Plz. Hop me.
Nitella [24]

1 = 4 quarters
2 = 8 quarters
3 = 12 quarters
4 = 16 quarters
5 = 20 quarters
6 = 24 quarters
7 = 28 quarters
ooops. too much
6 and 3/4 = 27 quarters

7 0
4 years ago
Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?
Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

sec^4 x + sec^2 x tan^2 x - 2 tan^4 x

Required

Simplify

(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2

Represent sec^2x with a

Represent tan^2x with b

The expression becomes

a^2 + ab- 2 b^2

Factorize

a^2 + 2ab -ab- 2 b^2

a(a + 2b) -b(a+ 2 b)

(a -b) (a+ 2 b)

Recall that

a = sec^2x

b = tan^2x

The expression (a -b) (a+ 2 b) becomes

(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

..............................................................................................................................

In trigonometry

sec^2x =1  +tan^2x

Subtract tan^2x from both sides

sec^2x - tan^2x =1  +tan^2x - tan^2x

sec^2x - tan^2x =1

..............................................................................................................................

Substitute 1 for sec^2x - tan^2x in (sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

(1) (sec^2x+ 2 tan^2x)

Open Bracket

sec^2x+ 2 tan^2x ------------------This is an equivalence

(secx)^2+ 2 (tanx)^2

Solving further;

................................................................................................................................

In trigonometry

secx = \frac{1}{cosx}

tanx = \frac{sinx}{cosx}

Substitute the expressions for secx and tanx

................................................................................................................................

(secx)^2+ 2 (tanx)^2 becomes

(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2

Open bracket

\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})

\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}

Add Fraction

\frac{1 + 2sin^2x}{cos^2x} ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

sin^2x + cos^2x= 1

Make sin^2x the subject of formula

sin^2x= 1  - cos^2x

................................................................................................................................

Substitute the expressions for 1  - cos^2x for sin^2x

\frac{1 + 2(1  - cos^2x)}{cos^2x}

Open bracket

\frac{1 + 2  - 2cos^2x}{cos^2x}

\frac{3  - 2cos^2x}{cos^2x} ---------------------- This is another equivalence

8 0
3 years ago
Which statement is true? Question 17 options: A) |–3| = 3 and |–4| = –4 B) –|3| = 3 and |4| = 4 C) |–3| = 3 and –|–4| = –4 D) |–
Mkey [24]
The second one because 4d x c is the correct answer
8 0
3 years ago
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