
$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Answer:
0.04326
Step-by-step explanation:
Answer:
Suppose we have a polynomial of degree N with a leading coefficient A and roots {x₁, x₂, ..., xₙ}
We can write this polynomial as:
P(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)
such that the terms:
(x - x₁), (x - x₂), etc...
are called the factors.
In this case, we know that the roots OF THE FACTORS
are:
(x = - 2)
(x = - (1 + √5))
(x = + 3i)
If the root of the polynomial is x = -2, then the factor should be:
(x + 2)
which is zero when we evaluate x in -2
Then the correct option is the first one.
To find the difference of given expression:

First step is to subtract the whole number5 and 3.
So, 5 - 3 = 2.
Now we can find the difference of fractions.
To subtract the fractions , we need to find the common denominator.
Common denominator of 3 and 5 is 15.
So, we need to make both the denominator equal to 15.

Similarly, 
Therefore, 
=
= 
So, the difference of given expression is
.
So, the correct choice is C.