The price of the burritos and tacos, using the system of linear equations, is equal to $32 and $26, respectively.
It is given that for a recent company party, Carmen spent $58 on one plate of burritos and one plate of tacos. For a company meeting, she spent $90 on two plates of burritos and one plate of tacos. We need to find the cost of each dish.
Let the costs of burritos and tacos be represented by the variables "x" and "y", respectively. We can write two equations, as given below.
x + y = 58
2x + y = 90
We will substitute the value of "y" from the first equation into the second equation.
y = 58 - x
2x + y = 90
2x + 58 - x = 90
x = 90 - 58
x = 32
Hence, the price of the burritos is $32. Now, we will substitute this value into the first equation.
y = 58 - x
y = 58 - 32
y = 26
Hence, the price of the tacos is $26.
The complete question is given below.
Carmen often orders fiesta trays from her favorite Mexican restaurant for company events. For a recent company party, she spent $58 on 1 plate of burritos and 1 plate of tacos. For a company meeting, she spent $90 on 2 plates of burritos and 1 plate of tacos. How much does each type of dish cost?
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Answer:
a
Step-by-step explanation:
because all top numbers can go into bottom numbers.
Looks like (0,1) and (2,4) are on the line.
(0,1) is the y intercept, b=1
The slope is m=(4 - 1)/(2 - 0) = 3/2
Answer: y = (3/2) x + 1
I believe there is a picture of the situation missing, but we still have all the info necessary to solve.
We take the height, 5, and divide by the slope, 1/12, getting 60. This is the length of the ramp.
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Answers:
The second term is 2
The fifth term is 23
The ninth term is 51
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Explanation:
To find the second term, replace every n with 2 and use PEMDAS to simplify
a(n) = -5+(n-1)(7)
a(2) = -5+(2-1)(7)
a(2) = -5+(1)(7)
a(2) = -5+7
a(2) = 2
The second term is 2
Similarly, plug in n = 5 to get the fifth term
a(n) = -5+(n-1)(7)
a(5) = -5+(5-1)(7)
a(5) = -5+(4)(7)
a(5) = -5+28
a(5) = 23
The fifth term is 23
Finally, replace every n with 9 to find the ninth term
a(n) = -5+(n-1)(7)
a(9) = -5+(9-1)(7)
a(9) = -5+(8)(7)
a(9) = -5+56
a(9) = 51
The ninth term is 51
