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3 years ago

Irregular polygons has sides that are not equal lenght and angles that are not equal?

Mathematics

1 answer:

olganol [36]3 years ago

8 0

Answer:

yeah it's true

Step-by-step explanation:

regular polygon have all equal side and all equal angle
IRREGULAR polygon have atleast one unequal side and one unequal angle

............THANKS.........

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Lisa is playing a video game in which she takes care of cats and dogs. She takes care of 4 cats for every 1 dog. If Lisa takes c

Vlada [557]

Answer:15 animals altogether
Explaination: But because it is

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3 years ago

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three times the sum of a number and -5 equals -6 times the sum of the number and -2. Find the number.

Rashid [163]

3(x-5)=-6(x-2)

3x-15=-6x+12

9x-15=12

9x=27

x=3

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3 years ago

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What is the gradient of the graph shown?

sladkih [1.3K]

Answer:

gradient = $\frac{1}{3}$

Step-by-step explanation:

calculate the gradient m using the gradient formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 6, 0) and (x₂, y₂ ) = (0, 2) ← 2 points on the line

m = $\frac{2-0}{0-(-6)}$ = $\frac{2}{0+6}$ = $\frac{2}{6}$ = $\frac{1}{3}$

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2 years ago

If you place a 20 ft ladder 4ft from the base of the wall. How high up will it reach? Round answer to the nearest tenth

xeze [42]

Answer:

h = 19.6 ft

Step-by-step explanation:

Given that,

A 20 ft ladder 4ft from the base of the wall.

The height of the ladder, H = 20 ft

The base distance, b = 4 ft

We need to find the height of the reach. Let it is P.

Using Pythagoras theorem,

$H^2=b^2+P^2\\\\P=\sqrt{H^2-b^2}\\\\P=\sqrt{20^2-4^2}\\\\=19.59\ ft$

P = 19.6 ft

So, the height is 19.6 ft.

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3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

3 years ago