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Verdich [7]
3 years ago
13

PLEASE HELP I AM GIVING 15 POINTS INSTEAD OF FIVE FOR ANSWERING PLEASSSEEE HEEEEELLLP

Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

Third Choice:

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Step-by-step explanation:

One line has

x + \dfrac{b}{2a} = \pm \dfrac{\sqrt{b^2 - 4ac}}{2a}

The next line's reason is that b/2a was subtracted from both sides.

The missing line is:

x = -\dfrac{b}{2a} \pm \dfrac{\sqrt{b^2 - 4ac}}{2a}

Then it simplifies to

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

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Rina8888 [55]

Answer:

No

Step-by-step explanation:

For a point to be the midpoint of a line segment, it must bisect it into two equal segments and be on the line segment (hence, colinear with the endpoints). All four B points are equidistant from points A and C, but aren’t colinear with A and C. Therefore, they aren’t all midpoints of line segment AC.

I hope this helps! :)

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3 years ago
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JulsSmile [24]

Answer:

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Step-by-step explanation:

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3 years ago
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slava [35]
What’s the question?
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Alex17521 [72]

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