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2 years ago

A line has a slope of 6 and passes through the (-4,-4)

Mathematics

1 answer:

Elenna [48]2 years ago

6 0

Answer:(2,-3) and (-10,-5)

Step-by-step explanation:

slope is mx+b/y so in short slope of six is 6/1 which is up six over 1 or down six back 1

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What is the value of x

pochemuha

This is the isosceles triangle. Therefore, the angles at the base are congruent.

We know that the sum of the measures of the angles in a triangle is 180°.

Therefore we have the equation:

$38^o+x^o+x^o=180^o$

$38^o+2x^o=180^o$ <em>subtract 38 from both sides</em>

$2x^o=142^o$ <em>divide both sides by 2</em>

$x^2=71^o$

<h3>Answer: x = 71.</h3>

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2 years ago

Evaluate each numerical expression

ioda

${3}^{4} - ( - 4)^{2} =81 - (16) = 65$

I hope I helped you^_^

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2 years ago

Read 2 more answers

Consider the scatter plot.

Leno4ka [110]

<u>Answer:</u>

The correct answer option is: The y-intercept of the line of best fit shows that when time started, the distance was 5 feet.

<u>Step-by-step explanation:</u>

We are given a scatter plot with a best fit line as shown on the given graph.

The equation of the best fit line is given by:

y = 0.75x + 5

So with the help of the equation and by looking at the given graph, we can conclude about the representation of the y intercept that the the y-intercept of the line of best fit shows that when time started, the distance was 5 feet.

Since the distance shown on the y axis is already 5 when the time started at 0 minutes.

4 0

2 years ago

Which is not a zero of the following function!?<br> f(x)=x3+3x2-x-3

nata0808 [166]

Answer:

Step-by-step explanation:

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2 years ago

If a spring is oscillating (moving) according to the velocity equation v(t) = 2sin(t) (in ft/s), then what is its displacement o

Feliz [49]

ANSWER

4 ft

EXPLANATION

The velocity equation of the oscillating spring is given by the function.

$v(t)=2 \sin(t) \: \: {ms}^{ - 1}$

To find the displacement function, we need to to Integrate the velocity function.

$s(t) = \int \: 2 \sin(t) dt$

$s(t) = - 2 \cos(t) + k$

At time t=0, there was no displacement.

This implies that,

$s(0) = 0$

$0= - 2 \cos(0) + k$

$0= - 2 + k$

$k = 2$

The displacement function then becomes,

$s(t) = - 2 \cos(t) + 2$

To find the displacement over the first π seconds, we put

$t = \pi$

into the equation for the displacement to get,

$s(\pi) = - 2 \cos(\pi) + 2$

$s(\pi) = - 2 ( - 1) + 2$

$s(\pi) = 2 + 2 =4 ft$

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3 years ago