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marissa [1.9K]
3 years ago
7

The owner of the Carousel Art Gallery receives a commission of 20% on paintings that are sold on consignment. Find the commissio

n on a painting that sold for $22,500.​
Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

So, $4,500 is the commission on the painting.

Step-by-step explanation:

Selling Price of the painting =  $22,500.​

Commission Percentage = 20%

Now, we know that commission is always applied on the selling price of the object.

So, 20% of $22, 500 = \frac{20}{100}  \times 22,500  = 4,500

So, 20% of $22,500 = $4,500

So, $4,500 is the commission on the painting sold at the gallery.

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3 years ago
25+ -8 equals I really need help
Nimfa-mama [501]

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7 0
3 years ago
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Jillian walked 0.5 miles before she started jogging at an average pace of 5 miles per hour. The equation d = 0.5 + 5t can be use
viktelen [127]
For this case we have the following equation:
 d = 0.5 + 5t
 We will describe the equation step by step.
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 t: independent variable that indicates the number of hours
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3 0
3 years ago
Read 2 more answers
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
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