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marissa [1.9K]
3 years ago
7

The owner of the Carousel Art Gallery receives a commission of 20% on paintings that are sold on consignment. Find the commissio

n on a painting that sold for $22,500.​
Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

So, $4,500 is the commission on the painting.

Step-by-step explanation:

Selling Price of the painting =  $22,500.​

Commission Percentage = 20%

Now, we know that commission is always applied on the selling price of the object.

So, 20% of $22, 500 = \frac{20}{100}  \times 22,500  = 4,500

So, 20% of $22,500 = $4,500

So, $4,500 is the commission on the painting sold at the gallery.

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Question 13
kicyunya [14]

Answer:

The c intercept is 42

The t intercepts are: 6, -1 and 7

Step-by-step explanation:

Given

c(t) = (t - 6)(t +1)(t-7)

Solving (a): The c intercept

Simply set t to 0

c(t) = (t - 6)(t +1)(t-7)

c(0) = (0 - 6)(0 +1)(0-7)

c(0) = (- 6)(1)(-7)

c(0) = 42

Solving (b): The t intercept

Simply set c(t) to 0

c(t) = (t - 6)(t +1)(t-7)

(t - 6)(t +1)(t-7) = 0

Split

t - 6= 0,\ \ t +1= 0,\ \ t-7 = 0

Solve for t

t = 6,\ \ t =-1,\ \ t=7

4 0
3 years ago
Y=9 11 13 15 x= -17 -1 6 27 is it a direct or inverse variation
dybincka [34]
It would be a direct variation.
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3 years ago
What is 1x + 3x when x=1
rodikova [14]

Answer:

x therefore will be equal to 4

8 0
3 years ago
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3 years ago
What is the probability of the complement of rolling a number less than 5 by using a six-sided die?
Inessa05 [86]
<h3><u>Answer:</u></h3>

Hence, the probability of the complement of rolling a number less than 5 by using a six-sided die is:

1/3

<h3><u>Step-by-step explanation:</u></h3>

Let A denote the event of rolling a number less than 5 in a six-sided die.

Now, we know that the Total outcomes are: 6

since, the sample space is given as: {1,2,3,4,5,6}

Also Number of favorable outcomes are: 4

since the numbers which are less than 5 are {1,2,3,4}

Now we have to find:

P(A^c)

where P denotes the probability of an event and A^c denote the complement of event A.

We know that:

P(A^c)=1-P(A)

Now,

P(A)=\dfrac{4}{6}\\\\P(A)=\dfrac{2}{3}

Hence,

P(A^c)=1-\dfrac{2}{3}\\\\P(A^c)=\dfrac{3-2}{3}\\\\P(A^c)=\dfrac{1}{3}

Hence, the probability of the complement of rolling a number less than 5 by using a six-sided die is:

1/3

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