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muminat
3 years ago
13

Negative 24 divided 15

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

-1.6

Step-by-step explanation:

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46 divided by 5 long divison
DIA [1.3K]
9.2 (b) is the answer hope this helped!
5 0
2 years ago
Eric is told by his doctor that he needs to lose 15 pounds. If Eric now weights 285 pounds,then by what percentage should Eric w
tatuchka [14]

Answer:

5.26%

Step-by-step explanation:

15/285=x/100. 15 is the amount of weight he wants to lose. x=5.26%

3 0
2 years ago
In a recent year, a sample of grade 8 Washington State public school students taking a mathematics assessment test had a mean sc
Daniel [21]

Answer:

The  number is  N  =1147 students

Step-by-step explanation:

From the question we are told that

    The population mean is  \mu  =  281

     The standard deviation is  \sigma  =  34.4

    The sample size is  n = 2000

percentage of the would you expect to have a score between 250 and 305 is mathematically represented as

      P(250 <  X <  305 ) =  P(\frac{ 250 - 281}{34.4 }  <  \frac{X - \mu }{\sigma }  < \frac{ 305 - 281}{34.4 }   )

Generally  

             \frac{X - \mu }{\sigma }  =  Z  (Standardized \ value \  of  \  X )

So  

         P(250 <  X <  305 ) =  P(-0.9012<  Z

       P(250 <  X <  305 ) = P(z_2 < 0.698 ) -  P(z_1 <  -0.9012)

From the z table  the value of  P( z_2 < 0.698) =  0.75741

                                         and  P(z_1 < -0.9012) =  0.18374

     P(250 <  X <  305 ) = 0.75741 - 0.18374

      P(250 <  X <  305 ) =  0.57

The  percentage is  P(250 <  X <  305 ) =  57\%

The  number of students that will get this score is

           N  = 2000 * 0.57

           N  =1147

6 0
3 years ago
What is the answer to this question ?
mixer [17]
What the heck is this
5 0
2 years ago
If EFH = (5x + 1)°, HFG = 62°, and EFG = (18x + 11)°, find EFH
olga55 [171]

Given:

Consider the below figure attached with this question.

∠EFH = (5x + 1)°, ∠HFG = 62°, and ∠EFG = (18x + 11)°

To find:

The measure of ∠EFH.

Solution:

From the figure it is clear that ∠EFG is divide in two parts ∠EFH and ∠HFG. So,

\angle EFG=\angle EFH+\angle HFG

18x+11=(5x+1)+(62)

18x+11=5x+63

Isolate variable terms.

18x-5x=63-11

13x=52

Divide both sides by 13.

x=\dfrac{52}{13}

x=4

The value of x is 4.

\angle EFH=(5x+1)^\circ

\angle EFH=(5(4)+1)^\circ

\angle EFH=(20+1)^\circ

\angle EFH=21^\circ

Therefore, the measure of ∠EFH is 21°.

8 0
3 years ago
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