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svetlana [45]
3 years ago
9

1.5meters line 1.2 meters wide what is the area

Mathematics
2 answers:
Zina [86]3 years ago
8 0
Area is easy
Area = length x breadth
= 1.5 x 1.2
=1.8
Wittaler [7]3 years ago
3 0

Answer:

1.8m²

Step-by-step explanation:

Area = Length × Width

Area = 1.5m × 1.2m

Area = 1.8m²

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Which statement is true about the terms of the linear expression 13-4x in standard form?
AysviL [449]

Answer:

B) b=13

Step-by-step explanation:

13-4x is the same as -4x+13

8 0
2 years ago
An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 37 type K batteries and a sample of 58
Olegator [25]

Answer:

Hypothesis Test states that we will accept null hypothesis.

Step-by-step explanation:

We are given that an engineer is comparing voltages for two types of batteries (K and Q).

where, \mu_1 = true mean voltage for type K batteries.

           \mu_2 = true mean voltage for type Q batteries.

So, Null Hypothesis, H_0 :  \mu_1 = \mu_2 {mean voltage for these two types of

                                                        batteries is same}

Alternate Hypothesis, H_1 : \mu_1 \neq \mu_2 {mean voltage for these two types of

                                                          batteries is different]

<em>The test statistics we use here will be :</em>

                     \frac{(X_1bar-X_2bar) - (\mu_1 - \mu_2) }{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  follows t_n__1 + n_2  -2

where, X_1bar = 8.54         and     X_2bar = 8.69

                s_1  = 0.225       and         s_2     =  0.725

               n_1   =  37           and         n_2     =  58

               s_p = \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} } =   \sqrt{\frac{(37-1)0.225^{2}+(58-1)0.725^{2}  }{37+58-2} }  =  0.585               Here, we use t test statistics because we know nothing about population standard deviations.

     Test statistics =  \frac{(8.54-8.69) - 0 }{0.585\sqrt{\frac{1}{37}+\frac{1}{58}  } } follows t_9_3

                             = -1.219

<em>At 0.1 or 10% level of significance t table gives a critical value between (-1.671,-1.658) to (1.671,1.658) at 93 degree of freedom. Since our test statistics is more than the critical table value of t as -1.219 > (-1.671,-1.658) so we have insufficient evidence to reject null hypothesis.</em>

Therefore, we conclude that mean voltage for these two types of batteries is same.

6 0
3 years ago
What is the volume of the cylinder below?​ ​
mixas84 [53]

the volume of the cylinder is d)168 units

5 0
3 years ago
Read 2 more answers
What is the vertex of the parabola y=2x2+20x-15?<br><br> (5, 135)<br> (-5, -165)<br> (-5, -65)
maria [59]

Answer:

-296=2×2+20×-15that is the answer

Step-by-step explanation:

you need to calculate the equation step by step to get to the answer

5 0
3 years ago
A survey reported that 5% of Americans are afraid of being alone in a house at night. If a random sample of 20 Americans is sele
liq [111]

Answer:

5.96% probability that exactly 3 people in the sample are afraid of being alone at night.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are afraid of being alone at night, or they are not. The probability of a person being afraid of being alone at night is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of Americans are afraid of being alone in a house at night.

This means that p = 0.05

If a random sample of 20 Americans is selected, what is the probability that exactly 3 people in the sample are afraid of being alone at night.

This is P(X = 3) when n = 20. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{20,3}.(0.05)^{3}.(0.95)^{17} = 0.0596

5.96% probability that exactly 3 people in the sample are afraid of being alone at night.

5 0
3 years ago
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