<span>assume z = ax for simplicity
z(z) = a(ax) = a^2x
let a^2x = 1/16x and solve for a </span>
Answer:
2000
Step-by-step explanation:
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.
So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.
f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
Answer:
Option A is correct.
The given expression :
then;

Step-by-step explanation:
Given the expression: 
Cross multiplication the given expression following steps are as follow;
- Multiply numerator of the left-hand fraction by the denominator of the right-hand fraction
- Also, Multiply numerator of the right-hand fraction by the denominator of the left-hand fraction.
- then, set the two products equal to each other.
Using cross multiplication, on the given expression;

First multiply the numerator of the left hand fraction(i.e,a ) by the denominator of the right hand fraction (i,e a)
we have;

Simplify:
[1]
now, multiply numerator of the right-hand fraction( i.e, 9) by the denominator of the left-hand fraction (i.e, 4 ) in [1]
we have;

Simplify:

Therefore, the given expression is equal to: 