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KatRina [158]
2 years ago
9

Please help with this question!

Mathematics
1 answer:
Nostrana [21]2 years ago
7 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

a ) Two matrices cannot be multiplied.

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

b )

The answer is | 20 - 4 - 12 |

| 8 2 19 - |

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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Simplify the expression:<br> (1 2/7)(-4 1/5)
stealth61 [152]

Answer:

-27/5 or -5 2/5

Step-by-step explanation:

Simplify

1 2/7 to 9/7

-4 1/5 to -21/5

multiply together

(9)(-21)/(7)(5)

-189/35

u can simplify by diving by 5 to get

-27/5

4 0
3 years ago
PLEASE HELP ME GEOMETRY
Aloiza [94]
Answer is B. second choice

Segments DE and AC are parallel by construction


4 0
3 years ago
10 percent increase of $29000 over 5 years,will give brainly is urgent
Tema [17]

Answer:

$43,500

Step-by-step explanation:

10 percent increase of $29,000

10% = 0.10

29,000*0.10 = 2,900

So 2,900 a year

so 2,900*5 = 14,500

Then add

29,000+14,500 = 43,500

8 0
3 years ago
How many ways are there to assign 8 visiting different studetns to one Stony Brook summer course, chossing from Calculus I, Line
Dmitry_Shevchenko [17]

Answer:

56 ways

Step-by-step explanation:

Number of ways is given by n combination r (n!/(n - r)!r!)

n = total number of students = 8, r = the number of summer courses = 3

Number of ways = 8 combination 3 = 8!/(8-3)!3! = 8!/5!3! = 8×7×6×5!/5!×6 = 8×7 = 56 ways

6 0
3 years ago
Raíz cuadrada de 864
marshall27 [118]

Raíz cuadrada de 864

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

The general equation of ellipse is given as, x2a2+y2b2=1 x 2 a 2 + y 2 b 2 = 1 , where, a is length of semi-major axis and b is length of semi-minor axis.

centro: (0,0)

focus : (0, -√28) , (0, √28)

eje conjugado = 2√3

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

de los focos podemos obtener que: √28

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b = √3

podemos utilizar la siguiente fórmula para obtener a:

si despejamos a en la ecuación obtenemos lo siguiente:

ahora podemos sustituir los valores:

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

si graficamos la hipérbola, queda como en el documento adjunto.

To learn more hipérbola

Visit : brainly.com/question/24223341

#SPJ9

8 0
1 year ago
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