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Vesnalui [34]
3 years ago
13

Use the Distance Formula to find the distance between (5, - 4) and (0, 8).

Mathematics
1 answer:
gogolik [260]3 years ago
8 0

Answer:

13 units

Step-by-step explanation:

Let d be the distance between given points.

\therefore \: d =  \sqrt{ {(5 - 0)}^{2} + ( - 4 - 8)^{2}  }  \\  \hspace{16 pt}=  \sqrt{ {(5)}^{2} + ( - 12)^{2}  }  \\  \hspace{16 pt}=  \sqrt{ 25 + 144 } \\  \hspace{16 pt}=  \sqrt{ 169 }  \\  \therefore \: d =13 \: units \\

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Which expression represents "5 times the sum of 4 and y?"
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Answer:

5 x (4+y)

Step-by-step explanation:

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3 years ago
Please see the image and help with this homework problem. thank you!
dimulka [17.4K]

we have the function

E=\sin \frac{\pi}{14}t

Part a

For t=7

substitute in the given function

\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}

For t=14

\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}

For t=21

\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}

For t=28

\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}

For t=35

\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

so

Period=2pi/B

B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28

<h2>the period is 28 days</h2>
6 0
1 year ago
Asha is tiling the lobby of the school with one-foot square tiles. She has 6 bags
barxatty [35]

Answer:

60 tiles left over

Step-by-step explanation:

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2 years ago
Find the diameter of the object.
Anni [7]

Answer:

1 \frac{1}{5} centimeters

Step-by-step explanation:

The diameter is equal to the radius × 2. We know that the radius is equal to 3/5 centimeters.

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This equals \frac{6}{5}, or 1 \frac{1}{5} cm.

5 0
2 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
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In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
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