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3 years ago

Can someone help me with this I'll give a crown thing please hurry!

Mathematics

1 answer:

gulaghasi [49]3 years ago

6 0

Answer:

1) 1: 107

2: 73

3: 107

4: 73

5: 107

6: 73

7: 107

8: 73

3) 1: 128

2: 52

3: 128

4: 52

5: 128

6: 52

7: 128

8: 52

Step-by-step explanation:

Vertical, corresponding, alternate exterior, and alternate interior angles are all congruent (equal).
Angles such as same side exterior and same-side interior are supplementary; meaning these angles add up to 180°.

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Graph the system of equations.

Y_Kistochka [10]

Answer:

Step-by-step explanation:

I cannot use the line tool for you, but I can rewrite the equations

y = -x + 4 is good enough

Two points for this graph:

x = 0 -> y = 4 gives the point (0, 4)

x = 1 -> y = 3 gives the point (1, 3)

18x + 6y = -6

6y = -18x - 6

y = -3x - 2

Two ponts for this graph:

x = 0 -> y = -2 gives the point (0, -2)

x = 1 -> y = -5 gives the point (1, -5 )

4 0

3 years ago

Read the word problem below. Chan rows at a rate of eight miles per hour in still water. On Wednesday, it takes him three hours

Romashka-Z-Leto [24]

Answer:

its A

Step-by-step explanation:

i literally just took the test

3 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So $n = 6, s = \frac{106}{\sqrt{6}} = 43.27$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 523}{43.27}$

$Z = -2.61$

$Z = -2.61$ has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0

3 years ago

Jessica has just purchased a new purse in the shape of a rectangular box to match her favorite shoes. The purse has a length of

Nostrana [21]

The volume would be 768 cm^3

6 0

3 years ago

Which of the transformations below CANNOT be used to create an image that is congruent

maksim [4K]

Rotation,reflections,and translations are isometric. That means that these transformations do not change the size of the figure. If the size and shape of the figure is not changed, then the figures are congruent.

7 0

3 years ago

Can someone help me with this I'll give a crown thing please hurry!​

Can someone help me with this I'll give a crown thing please hurry!