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3 years ago

40 POINTS!!!! ANSWER CORRECTLY PLZ

Mathematics

1 answer:

Grace [21]3 years ago

7 0

Answer:

5. ○ $\displaystyle \frac{25}{48}$

4. ○ $\displaystyle \frac{25}{46}$

3. ○ $\displaystyle \frac{31}{100}$

2. ○ $\displaystyle \frac{3}{4}$

1. ○ $\displaystyle \frac{27}{50}$

Step-by-step explanation:

5. $\displaystyle \frac{25}{23 + 25} = \frac{25}{48}$

4. $\displaystyle \frac{25}{46} = \frac{25}{21 + 25}$

3. $\displaystyle Flat-out\:given\:to\:you$

2. $\displaystyle \frac{21 + 23 + 31}{100} = \frac{75}{100} = \frac{3}{4}$

1. $\displaystyle \frac{31 + 23}{100} = \frac{54}{100} = \frac{27}{50}$

I am joyous to assist you anytime.

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Y=-×+1 and y=2×+4 how many solutions when graphed

dedylja [7]

Answer:

One solution (-1,2)

Step-by-step explanation:

Since these two linear equations have different slopes, different y-intercepts, and are indeed linear, these equations will only have one crossing when graphed, and hence one solution.

To find that solution, we can simply set the equations equal to each other.

y = -x + 1

y = 2x + 4

-x + 1 = 2x + 4

-3 = 3x

-1 = x

Now plug that value back into one of the equations:

y = -x + 1

y = -(-1) + 1

y = 2

So now you know the crossing for these two equations occurs at (-1,2).

Cheers.

3 0

3 years ago

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

bearhunter [10]

The question is incomplete. Here is the complete question:

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.

Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?

Answer:

40.13%

Step-by-step explanation:

Let 'A' be the event of not missing a target in 10 attempts.

Therefore, the complement of event 'A' is $\overline A=\textrm{Missing a target at least once}$