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marusya05 [52]
3 years ago
15

What is the scale factor from ADEF to AABC? 10 6 20 12 А 7 14

Mathematics
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

The scale factor is 1/2

Step-by-step explanation:

Given

\triangle DE F and \triangle ABC

Required

The scale factor from \triangle DE F to \triangle ABC

Take a corresponding side in both triangles.

We have:

DE= 20     AB = 10

The scale factor from \triangle DE F to \triangle ABC is:

k =\frac{AB}{DE}

k =\frac{10}{20}

k =\frac{1}{2}

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£5832 is shared equally between 9 people. How much does each person get?
mrs_skeptik [129]

Answer:

648

Step-by-step explanation:

5832÷9=648

I'm not sure what else to put for the explanation.

3 0
2 years ago
Read 2 more answers
How do I solve this math problem?
Nat2105 [25]

Answer: 4x² + 4x - 2 - \frac{3}{2x+3}

<u>Step-by-step explanation:</u>

You can use either synthetic or long division.  I am using synthetic division:

2x + 3 = 0   ⇒   x = -\frac{3}{2}

 -\frac{3}{2}   |    4    10    4    -6

       <u>|    ↓    -6    -6    3 </u>

            4     4    -2   -3  ← <em>-3 is the remainder</em>

            ↓     ↓     ↓

           4x² +4x  -2  ← <em>factored polynomial</em>

3 0
3 years ago
0 ÷ 0 = 1
TEA [102]

Answer:

0/0 = undefined not 1

Step-by-step explanation: Undefined means there are no solutions possible for the operations in view. The example in question is itself wrong. n/0 is infinite but not undefined. 0/0 is undefined

7 0
2 years ago
Tan(-212°)=____.<br><br> 1. -cot 32°<br> 2. tan 32°<br> 3. cot 32°<br> 4. -tan 32°
Marrrta [24]

Answer:

4. -\tan 32°

Step-by-step explanation:

Given:

The tangent of the angle is given as:

\tan (-212\°)

Since the angle is negative, it means that it is measured in the clockwise direction as angles measured in clockwise direction are negative and that measured in counter clockwise directions are positive.

-212° when measured from counter clockwise direction will be equal to:

-212\°(Clockwise)=360-212=148\°(CCW)

Therefore, \tan (-212\°) = \tan (148\°)

Now, we have the identity for tan as:

\tan(\pi-\theta)=-\tan \theta

Here, \theta=148\°

Therefore,

-\tan (148\°)=\tan(180-148)\\-\tan(148\°)=\tan(32\°)\\\textrm{Multiplying both sides by -1, we get:}\\-1(-\tan(148\°)=-1\times \tan(32\°)\\\\\tan(148\°)=-\tan(32\°)

Hence, \tan (-212\°) = \tan (148\°) = -\tan 32°

5 0
2 years ago
11. Keng creates a painting on a rectangular canvas with a width that is four inches longer
GrogVix [38]

Part A

<h3>Answer:  h^2 + 4h</h3>

-------------------

Explanation:

We multiply the length and height to get the area

area = (length)*(height)

area = (h+4)*(h)

area = h(h+4)

area = h^2 + 4h .... apply the distributive property

The units for the area are in square inches.

===========================================================

Part B

<h3>Answer:  h^2 + 16h + 60</h3>

-------------------

Explanation:

If we add a 3 inch frame along the border, then we're adding two copies of 3 inches along the bottom side. The h+4 along the bottom updates to h+4+3+3 = h+10 along the bottom.

Similarly, along the vertical side we'd have the h go to h+3+3 = h+6

The old rectangle that was h by h+4 is now h+6 by h+10

Multiply these expressions to find the area

area = length*width

area = (h+6)(h+10)

area = x(h+10) ..... replace h+6 with x

area = xh + 10x .... distribute

area = h( x ) + 10( x )

area = h( h+6 ) + 10( h+6 ) .... plug in x = h+6

area = h^2+6h + 10h+60 .... distribute again twice more

area = h^2 + 16h + 60

You can also use the box method or the FOIL rule as alternative routes to find the area.

The units for the area are in square inches.

6 0
3 years ago
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