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nalin [4]
3 years ago
8

Okay guys please y’all really help me ... I never get help

Mathematics
1 answer:
ad-work [718]3 years ago
5 0
Well, Brainly really doesn't like questions that are lifted straight out of exams, tests, or quizzes, so there's only so much I can say.

... You've GOT the formula for the height h at any time t .

... It TELLS you to find t when h=0.

... So write the equation

-16 t^2 + 32 t = 0

and then solve the equation to find t .

You'll find two solutions for t .
One of them is. t=0 .
This reveals the mind-blowing fact that the instant before the rocket was launched, at t=0, the rocket was on the ground.
The other solution for t will tell you how many seconds after launch the rocket is back on the ground.
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The quotient of 25 and t plus 6 is the same as twice t plus 1. Turn into equation!
KiRa [710]
25/t + 6 = 2t + 1
solve the equation from there
(1- 6)
25/t = 2t + -5
25/t x 2t = -5
50t = -5
t = -1/10


5 0
3 years ago
Read 2 more answers
Meg is building a rectangular prism with cubes. Which is the volume of Meg's<br> rectangular prism?
svet-max [94.6K]

Answer:

48

Step-by-step explanation: 4x8=32 2x8=16 32+16=48 :)

3 0
3 years ago
Fred's cafe uses 2 bags of coffee every day. How long will 2/3 of a bag of coffee last?
Arte-miy333 [17]
1 and 1/3----------Hope I helped....
3 0
3 years ago
How many solutions does 5x+2=3x+8 have (you dont have to put the actual solution)
Ray Of Light [21]

Answer:

one

Step-by-step explanation:

there are no equal variables

4 0
3 years ago
I've tried out this question so many different ways and I haven't been able to get it. I put 320 ft/s into the original equation
Xelga [282]
The equation is s=144t - 16t², s being the distance and V=144 ft/s

a)The maximum (or minimum) is reached when the derivative of s = 0

 s' = 144 - 32t = 0  and t= 9/2  or 4.5 second (time needed to reach the max
Now plug t= 4.5 in the original equation and you will find s = 324 ft

(Why it's a max and not a minimum: because 2nd derivative is negative and equals s" = -32)

b) Velocity of the ball: distance (up) s=320 ft, time that means:
 320 =144t - 16t² (solve for x) -16t²+144t-320 = 0, t₁ =4 and t₂ =5 (t₂ is not valid since max time to reach summit is 4.5) so t =4s , distance = 320. so the velocity at 320ft is 320/4 = 80 ft/s

c) Due to the symmetry of the parabola, the velocity at 320 ft on its way down = 80 ft/s
6 0
3 years ago
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