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Svetllana [295]
3 years ago
7

The mass of a piece of iron pyrite, or "fools gold", is 57.2 g. The volume is 11 cm3. What is the density of the piece of iron p

yrite? Hint: Density = massvolume
Density =
g/cm3
Mathematics
1 answer:
katen-ka-za [31]3 years ago
3 0

Answer:

<h2>5.2 g/cm³</h2>

Step-by-step explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{57.2}{11}  = 5.2 \\

We have the final answer as

<h3>5.2 g/cm³</h3>

Hope this helps you

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Assuming all model requirements for conducting the appropriate procedure have been​ satisfied, is the mean IQ of the students
Triss [41]

Answer:

Step-by-step explanation:

The right statistical procedure is by applying a hypothesis test that uses a single mean. Here, if we are to talk about comparison, it should be between the mean IQ of the students in the class and the national average IQ. The class is not for a comparison between two population means because it is viewed as the sample of the population. That is to say, the required task is to determine if the sample mean is greater than the population mean. We can conclude that this obeys a hypothesis test rather than a confidence interval.

6 0
3 years ago
If there are 400 ounces in 25 pounds, how many ounces are in 8 pounds
ladessa [460]
The answer is:  " 128 oz. " . 
_________________________________________________________
There are:  " 128 oz. " (in " 8 lbs." ) .
_________________________________________________________
Explanation:
________________________________________________________
Set up a proportion;  as a fraction; as follows:
________________________________________________________

 400/ 25  = x / 8 ; 

in which:  "x" = the number of "ounces [oz.] there are in "8 lbs." ;
________________________________________________________
We shall solve for "x" , the answer to the problem:

Cross-factor multiply:

25x = (400) * 8 ; 

→ 25x = 3200 ; 

Divide each side of the equation by "25" ; to isolate "x" on one side of the equation; & to solve for "x" ; 

→ 25x / 25 = 3200 / 25 ; 

→  x = 128 .
_________________________________________________________
Answer:  " 128 oz. " . 
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There are:  " 128 oz. " (in " 8 lbs." ) .
_________________________________________________________

Note of interest:  " 16 oz. =  1 lb. " (exact conversion). 

So;  "8 lbs.  <span>=  ?</span>  oz. " ; 

→  " 8 lbs. * (16 oz/ 1 lb)  =   ( 8 * 16) oz.  =  128 oz. ;  →  which is our answer!
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3 0
3 years ago
Read 2 more answers
Which ordered pair represents the y-intercept of the graph of the equation y = -3x - 9?
Mnenie [13.5K]
------------------------------------------------------------------------------------------
Equation
------------------------------------------------------------------------------------------
y = -3x - 9

------------------------------------------------------------------------------------------
Option 1
------------------------------------------------------------------------------------------
If I substitute x = -9, I should get y = 0

When x = -9
y = -3 (-9) - 9
= 18 (I did not get 0, wrong)


------------------------------------------------------------------------------------------
Option 2
------------------------------------------------------------------------------------------
If I substitute x = -3, I should get y = 0
y = -3(-3) - 9
y = 9 - 9 
y = 0 (Yes, I got 0, correct)


------------------------------------------------------------------------------------------
Option 3
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If I substitute x = 0, I should get y = -3
y = -3 (0) - 9
y = 0 - 9
y = -9 (I did not get -3, wrong)


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Option 4
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If I substitute x = 0, I should get y = -9
y = -3 (0) - 9
y = 0 - 9
y = -9 (Yes, I got -9, correct)


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Answer: (-3, 0) and (0, 9) are ordered pairs of the equation (Answer B, D)
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7 0
3 years ago
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

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• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

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… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

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• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
Add 5 1/5 and 4 3/5 as a fraction
kirill115 [55]

Answer:

9 and 4/5

Step-by-step explanation:

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