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Anastaziya [24]
3 years ago
9

On a coordinate plane, a line with a 90-degree angle crosses the y-axis at (0, 1), the x-axis at (1, 0), turns at (3, negative 2

), and crosses the x-axis at (5, 0).
What is the lowest value of the range of the function shown on the graph?

-infinity
-2
0
3
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer: 2

Step-by-step explanation: I did the test

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Please someone help me answer this ASAP
Vsevolod [243]

Answer:

0.28 represents the growth factor

Step-by-step explanation:

Given

f(x) = 5719(0.28)^x

Required

What does 0.28 represents

In a function:

y = ab^x

b represents the growth factor.

By comparison:

b = 0.28

So, this implies that: 0.28 represents the growth factor

5 0
3 years ago
You are planning to take to a trip to Montreal, Canada during the month of April and you want to bring clothing that is appropri
EastWind [94]

Answer:

1. E(Y) = 50.54°F

2. SD(Y) = 11.34°F

Step-by-step explanation:

We are given that The daily high temperature X in degrees Celsius in Montreal during April has expected value E(X) = 10.3°C with a standard deviation SD(X) = 3.5°C.

The conversion of X into degrees Fahrenheit Y is Y = (9/5)X + 32.

(1) Y = (9/5)X + 32

   E(Y) = E((9/5)X + 32) = E((9/5)X) + E(32)

           = (9/5) * E(X) + 32   {\because expectation of constant is constant}

           = (9/5) * 10.3 + 32 = 50.54

Therefore, E(Y), the expected daily high in Montreal during April in degrees Fahrenheit is 50.54°F .

(2) Y = (9/5)X + 32

    SD(Y) = SD((9/5)X + 32) = SD((9/5)X) + SD(32)

              = (9/5)^{2} * SD(X) + 0  {\because standard deviation of constant is zero}

              = \beacuse (9/5)^{2} * 3.5 = 11.34°F

Therefore, SD(Y), the standard deviation of the daily high temperature in Montreal during April in degrees Fahrenheit is 11.34°F .

6 0
3 years ago
Tim has a rectangular prism with a length of 10 centimeters, a width of 2 centimeters, and an unknown height. he needs to build
ozzi
The volume of the original prism is given by:
 V1 = (10) * (2) * (h)
 rewriting:
 V1 = 20h
 Where,
 h: height
 The volume of the second prism is given by:
 V2 = (5) * (w) * (h)
 We know that the height is the same.
 As the volume is the same then:
 (5) * (w) * (h) = 20h
 Clearing w we have:
 w = (20/5) = 4 cm
 Answer:
 
The width, in centimeters, of the new prism is:
 
w = 4cm
4 0
3 years ago
If integer k is equal to the sum of all even multiples of 15 between 295 and 615, what is the greatest prime factor of k?
ohaa [14]

Answer:

The greatest prime factor of k is 11.

Step-by-step explanation:

∵  LCM( 2, 15) = 30,

Thus, the even multiple of 15 must be multiple of 30,

That is, the even multiple of 15 between 295 and 615 are

300, 330, 360,..........600

Which is an AP,

Having first term, a = 300,

Common difference, d = 30,

If n be the number terms,

Last term = a+(n-1)d

=300+(n-1)30

=270 + 30n

\implies 270+30n = 600\implies 30n = 330\implies n = 11

Hence, the sum of the all even multiple of 15 from 295 to 615,

S_{11}=\frac{11}{2}(2(300)+(11-1)30)=\frac{11}{2}(600+300)=\frac{11}{2}(900)=11\times 450

According to the question,

S_{11}=k

⇒ k = 11 × 450 = 11 × 5 × 5 × 3 × 3 × 2

Hence, the greatest prime factor of k is 11.

3 0
3 years ago
Find the derivative of the algebraic function
Rama09 [41]
f(x)=x\left(3-\dfrac{4}{x+7}\right)=3x-\dfrac{4x}{x+7}=\dfrac{3x(x+7)}{x+7}-\dfrac{4x}{x+7}=\\=\dfrac{3x^2+21x-4x}{x+7}=
\dfrac{3x^2+17x}{x+7}\\
f'(x)=\dfrac{(6x+17)(x+7)-(3x^2+17x)}{(x+7)^2}\\
f'(x)=\dfrac{6x^2+17x+42x+119-3x^2-17x}{(x+7)^2}\\
f'(x)=\dfrac{119+42x+3x^2}{(x+7)^2}\Rightarrow \text{A}
7 0
4 years ago
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