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astraxan [27]
3 years ago
6

Find the value of this expression if x = 4 x^2 -8

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Let's solve your equation step-by-step.

x=4x2−8

Step 1: Subtract 4x^2-8 from both sides.

x−(4x2−8)=4x2−8−(4x2−8)

−4x2+x+8=0

For this equation: a=-4, b=1, c=8

−4x2+1x+8=0

Step 2: Use quadratic formula with a=-4, b=1, c=8.

x=−b±√b2−4ac2a

x=−(1)±√(1)2−4(−4)(8)2(−4)

x=−1±√129−8

x=18+−18√129 or x=18+18√129

Answer:

x=18+−18√129 or x=18+18√129

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Find the first four terms of the sequence<br> An=2a n-1,where a1=3
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The first four terms of the sequence are 3 , 6 , 12 , 24

Step-by-step explanation:

We need to find the first four terms of the sequence a_{n}=2a_{n-1}

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The first four terms of the sequence are 3 , 6 , 12 , 24

Learn more:

You can learn more about the sequences in brainly.com/question/1522572

#LearnwithBrainly

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