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astraxan [27]
3 years ago
6

Find the value of this expression if x = 4 x^2 -8

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Let's solve your equation step-by-step.

x=4x2−8

Step 1: Subtract 4x^2-8 from both sides.

x−(4x2−8)=4x2−8−(4x2−8)

−4x2+x+8=0

For this equation: a=-4, b=1, c=8

−4x2+1x+8=0

Step 2: Use quadratic formula with a=-4, b=1, c=8.

x=−b±√b2−4ac2a

x=−(1)±√(1)2−4(−4)(8)2(−4)

x=−1±√129−8

x=18+−18√129 or x=18+18√129

Answer:

x=18+−18√129 or x=18+18√129

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How to reduce into simpler terms.?
Sveta_85 [38]

Answer:

The simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

  • A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.
  • In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

\frac{45}{100}

\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}

\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5

\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}

45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20

so

\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}

\mathrm{Cancel\:the\:common\:factor:}\:5

     =\frac{9}{20}

Therefore, the simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

4 0
4 years ago
A game designer must decide how to color five buildings that are in a row. Using only the colors yellow, green, red, and blue, e
earnstyle [38]

Answer:

The total of ways the buildings can be painted are  = 4 \times 3  \times 2  \times 2  \times 1 = 48 ways.

Step-by-step explanation:

i) color five buildings that are in a row.

ii) any two neighboring buildings must be different colors

iii) the first third and fifth buildings must be different colors.

iv) the number of ways to paint the fist building are 4.

v) the number of ways to paint the second building are 3.

vi) the number of ways to paint the third building are 2.

vii) the number of ways to paint the fourth building are 2.

viii) the number of ways to paint the last building are 1.

ix) therefore the total of ways the buildings can be painted are

   = 4 \times 3  \times 2  \times 2  \times 1 = 48 ways.

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