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Amiraneli [1.4K]
3 years ago
14

Line AB passes through points A(–6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y = mx + b,

then m = – and b = –6–55 6.
Mathematics
2 answers:
Tresset [83]3 years ago
6 0
(-6,6)(12,3)
slope(m) = (y2 - y1) / (x2 - x1) = (3 - 6) / (12 - (-6) = -3 / 18 = -1/6

y = mx + b
slope(m) = -1/6
use either of ur points (12,3)....x = 12 and y = 3
now sub and find b, the y int
3 = -1/6(12) + b
3 = -12/6 + b
3 = -2 + b
3 + 2 = b
5 = b

so ur slope(m) = -1/6 and ur y int (b) = 5
Lana71 [14]3 years ago
4 0

Answer:5

Step-by-step explanation:

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amm1812

Answer:

{x = -3 , y = 10

Step-by-step explanation:

Solve the following system:

{y = 9 - x/3 | (equation 1)

{y = (2 x)/3 + 12 | (equation 2)

Express the system in standard form:

{x/3 + y = 9 | (equation 1)

{-(2 x)/3 + y = 12 | (equation 2)

Swap equation 1 with equation 2:

{-(2 x)/3 + y = 12 | (equation 1)

{x/3 + y = 9 | (equation 2)

Add 1/2 × (equation 1) to equation 2:

{-(2 x)/3 + y = 12 | (equation 1)

{0 x+(3 y)/2 = 15 | (equation 2)

Multiply equation 1 by 3:

{-(2 x) + 3 y = 36 | (equation 1)

{0 x+(3 y)/2 = 15 | (equation 2)

Multiply equation 2 by 2/3:

{-(2 x) + 3 y = 36 | (equation 1)

{0 x+y = 10 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{-(2 x)+0 y = 6 | (equation 1)

{0 x+y = 10 | (equation 2)

Divide equation 1 by -2:

{x+0 y = -3 | (equation 1)

{0 x+y = 10 | (equation 2)

Collect results:

Answer:  {x = -3 , y = 10

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