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Mazyrski [523]
3 years ago
9

A figure as vertices at (-2, 2), (-2, 6), (6, 6), (6, 2). Which shape best describes the figure?

Mathematics
1 answer:
attashe74 [19]3 years ago
5 0

Answer:

A rectangle

Step-by-step explanation:

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How do I simplify 5x + -2x + 6x + -x + 3x + 15x. ?
PtichkaEL [24]

hello there

the answer is 26x

Let's simplify step-by-step.

5x−2x+6x−x+3x+15x

=5x+−2x+6x+−x+3x+15x

Combine Like Terms:

=5x+−2x+6x+−x+3x+15x

=(5x+−2x+6x+−x+3x+15x)

=26x

hope this helps

3 0
3 years ago
Solve by factorising<br><br><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="abs
Paladinen [302]

Step-by-step explanation:

\underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} :

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

\underline{ \underline{ \text{Let's \: solve}}} :

\tt{ {x}^{2}  + 16x +  55 = 0}

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ \tt{ {x}^{2}  + (11 + 5)x + 55 = 0}

⤑ \tt{ {x}^{2}  + 11x + 5x +  55 = 0}

⤑ \tt{x(x + 11) + 5(x + 11) = 0}

⤑ \tt{(x + 5)(x + 11) = 0}

Either :

\tt{x + 5 = 0 \: \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \: Or :  \:  \:  x + 11 = 0}

\sf{⟶ x  = 0 - 5} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:⟶  x =  0 - 11

\tt{⟶x =  - 5 } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:     \:  \:⟶   x =  - 11

\red{ \boxed{ \boxed{ { \tt{Our \: final \: answer :  \boxed{ \underline{  \bold{ \tt{x  =  - 5 \: , - 11}}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0
3 years ago
If a cross section of the paperweight is cut perpendicular to the base but does not pass through the top vertex, which shape des
Montano1993 [528]
Rectangle shape paper weight
4 0
4 years ago
walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p
laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

Y(x) = (20+x)(60-2x)

Differentiating with respect to t ( time ),

Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x

Again differentiating with respect to t,

Y''(x) = -4

For maxima or minima,

Y'(x) = 0

⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0
3 years ago
Match the solid figure to the appropriate formula.
Zinaida [17]
<span>1. A = 1/4s squared, square root of 3      equilateral triangle
2. A = bh                                                  rectangle  
3. A = pi(r) squared                                  circle area 
4. A = 1/2 h (b1+ b2)                                trapezoid
5. C = pi(d)                                               circle circumference 
6. A = base x altitude                               parallelogram
7. A = 1/2(ap)                                           regular polygon
8. A = 1/2(bh)                                           triangle

</span><span>- regular polygon
- trapezoid
- parallelogram
- circle circumference
- equilateral triangle
- circle area</span>
4 0
3 years ago
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