Help me please answer thanks

Mathematics

1 answer:

lara31 [8.8K]3 years ago

3 0

Answer: (2,4)

Explanation: I hope this is what the question is asking for because I am in 9th grade hope this helps and I hope I am right

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Also this question tooo pleease, PS: what topic is this <br> Solve for x.

MrRissso [65]

This falls under geometry. The two labeled angles are congruent, which means the line segment between them (AD in the image) is a bisector of the angle at vertex A. Use the angle bisector theorem, which says that

$\dfrac{BD}{DC}=\dfrac{AB}{AC}\iff\dfrac{12}{(5+9x)-12}=\dfrac{15}{25}$

$\dfrac{12}{9x-7}=\dfrac35$

$20=9x-7$

$x=3$

8 0

3 years ago

PLEASSS HELP!!!!!!! I REALLY NEED HELP!!

loris [4]

Answer:

$\underline{ \boxed{x = 11} } \\ \underline{ \boxed{ABE = 55}}$

Step-by-step explanation:

$if \: the \: question \: is \to \\ \overline{AZ} \: \perp \: \overline{CD}, \: m \angle{ABE} = 5x, \\ and \\ \: m \angle{EBD } = 3x + 2\\ but \: m \angle{EBD } + m \angle{ABE} = 90 \\ hence \to \\ (3x + 2) + (5x) = 90 \\ 8x + 2 = 90 \\ 8x = 90 - 2 \\ 8x = 88 \\ x = \frac{88}{8} \\ \boxed{ x = 11} \\ \\ if \: x = 11, \: then \to \\ m \angle{ABE} = \: 5x = 5(11) \\ \boxed{m\angle{ABE} =55}$