The answer to the first question is D 60.
The answer to the second question is C 0.41.
Answer:
production cost f(x), in dollars, for x number of units produced by company 1:
f(x) = 0.05x^2 − 7x + 300
2) Table that represents the production cost g(x), in dollars, for x number of units produced by company 2:
x g(x)
0.6 899.58
0.8 899.52
1 899.50
1.2 899.52
1.4 899.58
3) Comparison: do a table for f(x) with the same x-values of the table for g(x).
x f(x) = 0.05x^2 − 7x + 300 g(x)
0.6 295.818 899.58
0.8 294.432 899.52
1 293.05 899.50
1.2 291.672 899.52
1.4 290.298 899.58
As you can see the values of f(x) are consistently lower than the values of g(x) for the same x-values.
The minimum production cost for company 2 is around 899.50 at x = 1, while the minimum production cost of company 1 is defintely lower (lower than 292.298 for sure, in fact if you find the vertex it is 55).
Answer: Based on the given information, the minimum production cost for company 2 is greater.
Step-by-step explanation:
Answer:
exact form- 61/8
mixed number form-7 5/8
?
Step-by-step explanation:
Answer:
The 95% confidence interval for the mean time for all players, in minutes, is: (7.95, 11.01).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.2622.
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 9.48 - 1.53 = 7.95 minutes.
The upper end of the interval is the sample mean added to M. So it is 9.48 + 1.53 = 11.01 minutes.
The 95% confidence interval for the mean time for all players, in minutes, is: (7.95, 11.01).