Answer:
yes
Step-by-step explanation:
y(x) is even or odd according as y(−x)=±y(x) . Here, #y(-x)=-(-x)^3=-(-x^3)=x^3=-y(x). So, y is an odd function of x.
Answer:
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
Let n represent the number.
2n+3 . . . . "doubled, then increased by 30"
3n -5 . . . . "five less than three times the number"
These two results are equal, so we have ...
2n +3 = 3n -5
8 = n . . . . . . . . . . add 5-2n
The number is 8.
Given a series, the ratio test implies finding the following limit:

If r<1 then the series converges, if r>1 the series diverges and if r=1 the test is inconclusive and we can't assure if the series converges or diverges. So let's see the terms in this limit:

Then the limit is:

We can simplify the expressions inside the absolute value:

Since none of the terms inside the absolute value can be negative we can write this with out it:

Now let's re-writte n/(n+1):

Then the limit we have to find is:

Note that the limit of 1/n when n tends to infinite is 0 so we get:

So from the test ratio r=0.4 and the series converges. Then the answer is the second option.