If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
Answer:
( x - 1) ( 2x + 3)
Step-by-step explanation:
It's actually the other way round.
2x^2- + x - 3
( 2x^2 - 2x) + (3x-3)
2x ( x-1 ) + 3( x-1)
( x - 1)(2x+3)
Its the other way around
HOPE IT HELPED
Answer:
32 students
Step-by-step explanation:
8 teams
32 students
Answer:
y = 84
Step-by-step explanation:
1) add 3 to both sides of your equation to cancel out the -3
end up with: (1/3)y + 14 = (1/2)y
2) multiply both sides of your equation by 2 to cancel out the (1/2)
end up with: (2/3)y + 28 = y
3) subtract (2/3)y from both sides of the equation to cancel out the positive (2/3)y
end up with: 28 = (1/3)y
4) multiply both sides of the equation by 3 to cancel out the (1/3)
end up with: 84 = y
We need to leave m alone on the right hand side, so let's move everything else to the left hand side.
First of all, we can subtract b from both sides to get
Now, we can divide both sides by c to get
And so we solved the expression for m, because we have written an expression in the form 
, where the right hand side doesn't depend on m.
