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Papessa [141]
2 years ago
6

%20%3Ab%20c%3A%20" id="TexFormula1" title="if a : b = 2 : 3 and b : c = 4 : 5 than find a :b c: " alt="if a : b = 2 : 3 and b : c = 4 : 5 than find a :b c: " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
grigory [225]2 years ago
8 0

Answer:

<em>a:b:c=8:12:15</em>

Step-by-step explanation:

<u>Combined Ratio</u>

We are given the ratios:

a:b=2:3

b:c=4:5

The combined ratio a:b:c will include all three variables in one single expression.

Before finding it, we must have a common number for the common variable (b). Since b is 3 in the first ratio and 4 in the second ratio, we must equate both by finding the LCM of 3 and 4=12, thus both ratios will be amplified as follows:

a:b=2:3=(2*4):(3*4)=8:12

b:c=4:5=(4*3):(5*3)=12:15

Now there is a common factor in both ratios, we can combine them removing the common factor:

a:b:c=8:12:15

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Please Help practice #3
algol [13]

Answer:

(2x+5)(4x+3)

Step-by-step explanation:

Given the expression 8x^2 + 26x + 15

Factorize

8x^2 + 26x + 15

= 8x^2 + 6x + 20x + 15

= 2x(4x+3) + 5 (4x+3)

= (2x+5)(4x+3)

Hence the factored form of the expression is (2x+5)(4x+3)

5 0
3 years ago
A production process produces 2% defective parts. a sample of 5 parts from the production is selected. what is the probability t
Lana71 [14]

Answer:

Probability of a sample that contains exactly two defective parts is .0037 or .37%

Step-by-step explanation:

As we know if P is the probability of achieving k results in n trials then probability formula is P = \binom{n}{k}p^{K}q^{n-k}

In this formula n = number of trials

                        k = number of success

                        (n-k) = number of failures

                         p = probability of success in one trial

                         q = (1-p) = probability of failure in one trial

In this sum n = 5

                  k = 2

number failures (n-k) = (5-2) = 3

                            p = 2% which can be written as .02

                            q = 98% Which can be written as .98

Now putting these values in the formula

                        P = \binom{5}{2}(.02)^{2}(.98)^{5-2}

                        P = \binom{5}{2}(.02)^{2}(.98)^{3}

                   \binom{5}{2}= 5!/3!2!    

                                              = 5×4×3×2×1/3×2×1×2×1

                                              = 5×2 =10

                                       P = 10×(.02)²×(.98)³

                                          = .0037 or .37%

4 0
3 years ago
Read 2 more answers
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arsen [322]

Answer:

The area of a circle is [tex]\pir^{2}[\tex] and the radius is 4 so we have 16π and substituting 3.14 for pi we get 50.24 .

Hope this helps!

8 0
3 years ago
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Ymorist [56]

Answer:

24

Step-by-step explanation:

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Sauron [17]

Answer:

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3

yes

Step-by-step explanation:

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So because the only transformation was a dilation that didn't significantly change the figure then we can say that both figures are similar.

8 0
3 years ago
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