Using the hypergeometric distribution, it is found that there is a 0.0002 = 0.02% probability that exactly 6 patients will die.
<h3>What is the hypergeometric distribution formula?</h3>
The formula is:
![P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20h%28x%2CN%2Cn%2Ck%29%20%3D%20%5Cfrac%7BC_%7Bk%2Cx%7DC_%7BN-k%2Cn-x%7D%7D%7BC_%7BN%2Cn%7D%7D)
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
The values of the parameters for this problem are:
N = 25, k = 6, n = 8.
The probability that exactly 6 patients will die is P(X = 6), hence:
![P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20h%28x%2CN%2Cn%2Ck%29%20%3D%20%5Cfrac%7BC_%7Bk%2Cx%7DC_%7BN-k%2Cn-x%7D%7D%7BC_%7BN%2Cn%7D%7D)
![P(X = 6) = h(6,25,8,6) = \frac{C_{6,6}C_{19,2}}{C_{25,8}} = 0.0002](https://tex.z-dn.net/?f=P%28X%20%3D%206%29%20%3D%20h%286%2C25%2C8%2C6%29%20%3D%20%5Cfrac%7BC_%7B6%2C6%7DC_%7B19%2C2%7D%7D%7BC_%7B25%2C8%7D%7D%20%3D%200.0002)
0.0002 = 0.02% probability that exactly 6 patients will die.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394
#SPJ1
The final answer should be -49/168.
Answer:
12.5 % decrease
Step-by-step explanation:
To find the percent loss
Take the original amount and subtract the new amount
2.4 -2.1 = .3
Divide by the original amount
.3/2.4 = .125
Multiply by 100 to change to a percent
12.5 %
This is the percent decrease
The volume would be 5 because in order to find volume you need to divide mass over density. V=m/d