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OLEGan [10]
3 years ago
13

A 6-meter wire will be cut into pieces that are each 0.15 meter in length. A 3-meter rope will be cut into pieces that are each

0.25 meter in length.
How many more pieces of wire than pieces rope will there be?
Mathematics
1 answer:
belka [17]3 years ago
4 0

Answer:

that will be 40(wire)-12(rope)=28parts

Step-by-step explanation:

6meter wire div by 0.15 eq to 40

3meter rope div 0.25 eq to 12

so we use 40-12=28parts

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It is the second graph.

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A bowl contains 25 balls numbered 1 to 25. A ball is drawn and its number is noted. Without replacing the first ball, another ba
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Step-by-step explanation:

n(S) = 25

Assume that O : odd numbers and E : even numbers,

n(O) = 13

n(E) = 25-13 = 12

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= 13/25 x 12/24

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4 years ago
A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the followin
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Answer:

(a) \sum x_i=56.68 and \sum x_i^2=197.46

(b) The sample variance is s^2=0.530 and the sample standard deviation is s=0.728

Step-by-step explanation:

(a)

The sum of these 17 sample observations is

\sum x_i=2.79\:+2.57+\:2.73\:+3.75\:+2.27+\:2.75+\:4.00+\:4.22+\:3.88+\:4.35+\:3.41+\:4.57+\:2.38+\:3.73\:+2.75+\:3.47+\:3.06\\\\\sum x_i=56.68

and the sum of their squares is

\sum x_i^2=2.79^2\:+2.57^2+\:2.73^2\:+3.75^2\:+2.27^2+\:2.75^2+\:4.00^2+\:4.22^2+\:3.88^2+\:4.35^2+\:3.41^2+\:4.57^2+\:2.38^2+\:3.73^2\:+2.75^2+\:3.47^2+\:3.06^2\\\\\sum x_i^2=197.46

(b)

The sample variance, denoted by s^2, is given by

s^2=\frac{S_{xx}}{n-1}

where S_{xx} =\sum x_i^2-\frac{(\sum x_i)^2}{n}

Applying the above formula we get that

S_{xx}=197.46-\frac{(56.68)^2}{17}\\\\S_{xx} =8.482

s^2=\frac{8.482}{17-1}=0.530

The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

s=\sqrt{s^2}

Applying the above formula we get that

s=\sqrt{0.530}=0.728

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