The distance from Jason’s house to the school is 0.5 kilometers. What is the distance in meters
2 answers:
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Answer:
a). ∠D = 56°
b). AD = √13
Step-by-step explanation:
(a) From the figure attached, ABCD is a trapezoid with parallel sides AB and CD. We have to find the measure of ∠D from the given figure.
From triangle ADE,
D =
D = 56.31
D ≈ 56°
Therefore, measure of ∠D is 56°.
(b). Now by applying Pythagoras theorem in ΔADE,
AD² = AE² + DE²
= 3² + 2²
AD² = 9 + 4
AD = √13
Length of AD is √13 in.
