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nekit [7.7K]
3 years ago
5

2. (04.02 LC)

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0
I think ninety-two hundredths
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Paige rides her bike around town. She can ride one half of a mile in 1 30 ith of an hour. If she continues to ride at the same p
oksano4ka [1.4K]
She could travel 15 miles in an hour
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4 years ago
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1 3/8 + 3 2/8 =<br><br> pls help me i have been on this for way to long
andrew11 [14]

Answer:

4.625

Step-by-step explanation:

4.625 Your welcome :)

4 0
3 years ago
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Help me out in this one pliz i need help
anyanavicka [17]
Hello : 
the general term is : an = a1×r^(n-1)
a1 : the first term....( a1 = 6)
r : the common ratio......( r = -1/3 )
when : n = 8     a8 is the eighth term :  a8 = 6×(-1/3)^7
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7 0
3 years ago
PLZZ HELP: A runner, training for a competition, ran on a track every day for 10 weeks. The first week he ran 8 kilometers each
Alekssandra [29.7K]

Answer:


Step-by-step explanation:

The values in column B were found by dividing both values in column A by 10. The values in column C were found by dividing both values in column B by 2. The other columns contain multiples of the values in column B.

If we look in column E, we can see that it would take her 45 minutes to run 6 miles.

If we look in column B, we can see that she could run 2 miles in 15 minutes.

If we look in column F, we can see that she is running 8 miles every 60 minutes (which is 1 hour), so she is running 8 miles per hour.

If we look in column C, we can see that her pace is 7.5 minutes per mile.

Solution: Finding a unit rate

If we divide 150 by 20, we get the unit rate for the ratio 150 minutes for every 20 miles.

150÷20=7.5

So the runner is running 7.5 minutes per mile. We can multiply this unit rate by the number of miles:

7.5minutesmile×6 miles=45 minutes

Thus it will take her 45 minutes to run 6 miles at this pace.

If it takes her 45 minutes to run 6 miles, it will take her 45÷3=15 minutes to run 6÷3=2 miles at the same pace.

If it takes her 15 minutes to run 2 miles, it will take her 4×15=60 minutes to run 4×2=8 miles at the same pace. Since 60 minutes is 1 hour, she is running at a speed of 8 miles per hour.

We found her pace in minutes per miles in part (a).

hope it helps


4 0
3 years ago
Prove the following identity ​
Deffense [45]

Answer:

sec(x)/(tan xsin(x))=cot^2 x+1 = Ture

Step-by-step explanation:

Verify the following identity:

sec(x)/(tan(x) sin(x)) = cot(x)^2 + 1

Hint: | Eliminate the denominator on the left hand side.

Multiply both sides by sin(x) tan(x):

sec(x) = ^?sin(x) tan(x) (cot(x)^2 + 1)

Hint: | Express both sides in terms of sine and cosine.

Write cotangent as cosine/sine, secant as 1/cosine and tangent as sine/cosine:

1/cos(x) = ^?sin(x)/cos(x) sin(x) ((cos(x)/sin(x))^2 + 1)

Hint: | Simplify the right hand side.

((cos(x)/sin(x))^2 + 1) sin(x) (sin(x)/cos(x)) = (((cos(x)^2)/(sin(x)^2) + 1) sin(x)^2)/(cos(x)):

1/cos(x) = ^?(sin(x)^2 (cos(x)^2/sin(x)^2 + 1))/cos(x)

Hint: | Put the fractions in cos(x)^2/sin(x)^2 + 1 over a common denominator.

Put cos(x)^2/sin(x)^2 + 1 over the common denominator sin(x)^2: cos(x)^2/sin(x)^2 + 1 = (cos(x)^2 + sin(x)^2)/sin(x)^2:

1/cos(x) = ^?sin(x)^2/cos(x) (cos(x)^2 + sin(x)^2)/sin(x)^2

Hint: | Cancel down ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)).

Cancel sin(x)^2 from the numerator and denominator. ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)) = (sin(x)^2 (cos(x)^2 + sin(x)^2))/(sin(x)^2 cos(x)) = (cos(x)^2 + sin(x)^2)/cos(x):

1/cos(x) = ^?(cos(x)^2 + sin(x)^2)/cos(x)

Hint: | Eliminate the denominators on both sides.

Multiply both sides by cos(x):

1 = ^?cos(x)^2 + sin(x)^2

Hint: | Use the Pythagorean identity on cos(x)^2 + sin(x)^2.

Substitute cos(x)^2 + sin(x)^2 = 1:

1 = ^?1

Hint: | Come to a conclusion.

The left hand side and right hand side are identical:

Answer: (identity has been verified)

3 0
2 years ago
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