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3 years ago

I’ll mark brainliest, thanks

Computers and Technology

2 answers:

Mrrafil [7]3 years ago

7 0

Answer:

if that is a tutorial, than just hit submit, the teacher doesn't see it.

Explanation:

i do online schooling on the same website

Mars2501 [29]3 years ago

3 0

\Yeah man, what the last guy said. On that website, teachers can't see tutorials so you can just submit it blank if you want. :)

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What are some options available in the Spelling and Grammar Checker in word?

denpristay [2]

Some options are add to dictionary, ignore once, ignore all, autocorrect, change, and change all.

6 0

3 years ago

Which of the following would be a valid method call for the following method? public static void showProduct (int num1, double n

Alenkinab [10]

Answer:

showProduct(int,double)

for example: showProduct(10,10.5) is the correct answer even showProduct(10,10.0) is also correct but showProduct(10.0,10.5) or showProduct(10,10) or showProduct(10.0,10) are wrong calls.

Explanation:

The code is

public static void showProduct (int num1, double num2){
int product;
product = num1*(int)num2;
System.out.println("The product is "+product);
}

showProduct is function which asks for two arguments whenever it is called, first one is integer and second one is of type double which is nothing but decimal point numbers. Generally, in programming languages, 10 is treated as integer but 10.0 is treated as decimal point number, but in real life they are same.

If showProduct( 10,10.0) is called the output will be 'The product is 100'.

Strange fact is that, if you enter showProduct(10,10.5) the output will remain same as 'The product is 100'. This happens because in the 3rd line of code,which is product=num1*(int)num2, (int) is placed before num2 which makes num2 as of type integer, which means whatever the value of num2 two is given, numbers after decimal is erased and only the integer part is used there.

This is necessary in JAVA and many other programming languages as you cannot multiply two different datatypes (here one is int and another is double). Either both of them should be of type int or both should be of type double.

3 0

2 years ago

You are a visitor at a political convention with delegates; each delegate is a member of exactly one political party. It is impo

Fed [463]

Answer:

The algorithm is as follows:

Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n)

Download txt

5 0

2 years ago

g Write a program that prompts the user for an integer n between 1 and 100. If the number is outside the range, it prints an err

grin007 [14]

Answer:

The cpp program is given below.

#include<iostream>

#include<iomanip>

using namespace std;

int main() {

// variables declared

int n;

int sum=0;

float avg;

{

// user input taken for number

cout<< "Enter a number between 1 and 100 (inclusive): ";

cin>>n;

if(n<1 || n>100)

cout<<" Number is out of range. Enter valid number."<<endl;

}while(n<1 || n>100);

cout<<" "<<endl;

// printing even numbers between num and 50

for(int num=1; num<=n; num++)

{

sum = sum + num;

}

avg = sum/n;

// displaying sum and average

cout<<"Sum of numbers between 1 and "<<n<<" is "<<sum<<endl;

cout<<"Average of numbers between 1 and "<<n<<" is ";

printf("%.2f", avg);

return 0;

}

OUTPUT

Enter a number between 1 and 100 (inclusive): 123

Number is out of range. Enter valid number.

Enter a number between 1 and 100 (inclusive): 56

Sum of numbers between 1 and 56 is 1596

Average of numbers between 1 and 56 is 28.00

Explanation:

The program is explained below.

1. Two integer variables are declared to hold the number, n, and to hold the sum of numbers from 1 to n, sum. The variable sum is initialized to 0.

2. One float variable, avg, is declared to hold average of numbers from 1 to n.

3. User input is taken for n inside do-while loop. The loop executes till user enters value between 1 and 100. Otherwise, error message is printed.

4. The for loop executes over variable num, which runs from 1 to user-entered value of n.

5. Inside for loop, all the values of num are added to sum.

sum = sum + num;

6. Outside for loop, average is computed and stored in avg.

avg = sum/n;

7. The average is printed with two numbers after decimal using the following code.

printf("%.2f", avg);

8. The program ends with return statement.

9. All the code is written inside main() and no classes are involved.

3 0

3 years ago

Write a function that receives two numbers, m and n and calculates and displays the sum of the integers from m to n. For example

Evgesh-ka [11]

Answer:

The program to this question as follows:

Program:

//header file

#include <stdio.h> //defining header file

void inc(int m,int n) //defining method inc

{

int sum, i; //declaring variable

sum=m; //holding value of m variable

for(i=++m;i<=n;i++) //loop for calculate number between given range

{

sum=sum+i; //adding value

}

printf("sum of the integer is : %d",sum);//print value

}

int main() //defining method

{

int m,n; //defining integer variable

printf("Enter m value: "); //message

scanf("%d",&m); //input value by user in variable

printf("Enter n value: "); //message

scanf("%d",&n);//input value by user in variable

inc(m,n); //calling method

return 0;

}

Output:

Enter m value: 3

Enter n value: 7

sum of the integer is :25

Explanation:

In the above code, an "inc" function is declared, that accepts integer parameters that are "m and n", inside the method two integer variable "sum and i" is declared, which is used in the loop.

The loop uses the user parameter to count value and uses the sum variable to calculate there sum.
In the main method, two integer variable n and m are declared, which take value from the user end, and at the last, we call the inc method, that prints sum value.

7 0

2 years ago