Based on the information given in the question, since Gina does not know how to write SQL commands and no forms have been created, the best option to generate the report is a query builder.

With the Query Builder, Gina can be able to search and also select and filter the database objects, while also creating relationships between the objects, and save queries despite not having any SQL knowledge.

4 0

3 years ago

#include #include int main( ) { int value = 10; int pid; value += 5; pid = fork( ); if (pid > 0 ) { value += 20; } printf(val

ss7ja [257]

Explanation:

To understand how this program is working let us print the variable value at different stages of the program so that we can understand how it is working.

Intitally, value=10 when it was declared.

Then we added 5 and it become value=15

then we used fork() function which creates a parent(orignal) and child(duplicate)

When fork() succeeds it returns the child pid to parent and returns 0 to the child. As you can see (pid > 0) condition is always true therefore the parent pid value becomes 35 ( 15+20) and the child pid value becomes 0.

#include <stdio.h>

#include <unistd.h>

int main( ) {

int value = 10;

printf("%d\n",value);

int pid;

value += 5;

printf("%d\n",value);

pid = fork( );

printf("%d\n",pid);

if (pid > 0 )

{

value += 20;

}

printf("%d\n",value);

return 0;

}

Output:

10 (initial value)

15 (modified value)

5343 (pid when fork is used)

35 (final modified value)

0 (child value)

15 (the parent value when fork was used)

8 0

4 years ago