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harina [27]
3 years ago
8

Express 34% as a fraction in simplest form. 34/100 8/25 17/50 3/4

Mathematics
1 answer:
Archy [21]3 years ago
7 0

Did you just state the answer? Because it seems like you just answered the question for us.

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CAN YOU ADD 2 TO PI TO GET A RATIONAL NUMBER
butalik [34]
No because Pi is an irrational number so adding 2 to Pi will also be irrational.

6 0
3 years ago
I need help, I got 80 and 90 but it said I was wrong...​
Anton [14]

Answer:

I think it is 90 and 100

Step-by-step explanation:

I used this equation: x is the speed of the slower train

910 = (5x + 10) + 5x

8 0
3 years ago
Read 2 more answers
Ricardo works in the marketing department of a game design company. His boss has offered to bonus the entire department of their
Stells [14]

Answer:

<h2>Approximately 4824 games </h2>

Step-by-step explanation:

Given that the sales made are 4,567 ,5430, 3998, 5,220,and 4,906

the average is (4567+5430+3998+5220+4906)/5

=24121/5

=4824.2

in the month of august let the sales be x

average= (4567+5430+3998+5220+4906+x)/6

the average for march to july is 4824.2

4824.2= (4567+5430+3998+5220+4906+x)/6

24121+x=4824.2*6

24121+x=28945.2

x=28945.2-24121

x=4824.2

approximately 4824 games

4 0
3 years ago
For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl
nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
3 0
3 years ago
Harlp needed ok thanks dudes
Ivanshal [37]

Solution:

<u>A few definitions...</u>

  • Rational number - Any integer, fraction, terminating decimal, or repeating decimal is classified as a rational number
  • Irrational number - All the real numbers which are not rational numbers.

<u>Option A - Rational or Irrational?</u>

  • 1/2 + 1/3

Since both are known as fractions, they are rational numbers.

<u>Option B - Rational or Irrational?</u>

  • √2 + 5/2

√2 is classified as an Irrational number because if it is simplified, it does not result in any integer, fraction, terminating decimal, or repeating decimal.

<u>Option C - Rational or Irrational?</u>

  • 1/√4 + 7/2
  • => 1/2 + 7/2
  • => 8/2 = 4

Since this is an integer, this is rational.

<u>Option D - Rational or Irrational?</u>

  • √9 + √4
  • => √3 x 3 + √2 x 2
  • => 3 + 2 = 5

Since this is an integer, this is rational.

In conclusion...

Option B is correct.

8 0
2 years ago
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